PLEASE URGENT URGENT URGENT CALCULUS HELP

Mathematics

1 answer:

love history [14]3 years ago

6 0

Answer:

Step-by-step explanation:

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The weight of mr nazeer is 7 times that of his son. What's the ratio of their weights?

Mekhanik [1.2K]

Answer:

Step-by-step explanation:

Let the weight of mr nazeer be x

Let the weight of his son be y

If the weight of mr nazeer is 7 times that of his son, then x = 7y

To get the ratio of their weight:

Ratio = weight of father/weight of son

Ratio = 7y/y

Ratio = 7/1

Ratio = 7:1

Hence the ratio of their weights is 7:1

3 0

3 years ago

Answer Question number 5 <br> Plzzzzzz

loris [4]

Answer:

Step-by-step explanation:

a = -4/3

d= -1 +4/3 =1/3

last term = 4 1/3 = 13/3

nth term = a +(n-1)d

$\frac{-4}{3}+(n-1)*\frac{1}{3}=\frac{13}{3}\\\\(n-1)*\frac{1}{3}=\frac{13}{3}-\frac{-4}{3}\\\\(n-1)*\frac{1}{3}=\frac{13+4}{3}\\\\(n-1)*\frac{1}{3}=\frac{17}{3}\\\\n-1=\frac{17}{3}*\frac{3}{1}\\\\n-1=17\\\\n=17+1=18$

Middle terms are 9the term and 10th term

$t_{9}=\frac{-4}{3}+8*\frac{1}{3}=\frac{-4}{3}+\frac{8}{3}=\frac{4}{3}\\\\t_{10}=\frac{-4}{3}+9*\frac{1}{3}=\frac{-4}{3}+\frac{9}{3}=\frac{5}{3}\\\\ t_{9}+t_{10}=\frac{4}{3}+\frac{5}{3}=\frac{9}{3}=3\\\\t_{9}+t_{10}=3$