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3 years ago

The width of a rectangular room is 60 percent of its length. the length of the room is 10 feet. what is the area of the room

2 answers:

5 0

To find the area of a rectangle, the equation is Area =Length x Width. Because the length is 10, to find the width, multiply it by 0.6. 10x0.6=6. then, take that answer, 6 and multiply by 10. This will give you 60 as your answer. 60 sq ft. squared basically.

blsea [12.9K]3 years ago

4 0

The width is 6 feet because 10•0.6=6

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Simplify -14x^3/x^3- 5x^4 where x=?

ki77a [65]

Step-by-step explanation:

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3 years ago

What is the square root of 49

ivann1987 [24]

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3 years ago

Mr. Jamieson plans to put some 3-pound math books in a box that can hold 26 pounds or less. The inequality 3b ≤ 26 describes the

solniwko [45]

Answer:

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Step-by-step explanation:

All we have to do is divide both sides by 3

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3 years ago

One plant container holds 14 seedlings, you have 1,113 seedlings. how many plant containers will hold all the seedlings.

Setler [38]

Answer: the answer wwas c

Step-by-step explanation:

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2 years ago

Read 2 more answers

curve before applying the theorem.)F(x, y) = y cos(x) − xy sin(x), xy + x cos(x), C is the triangle from (0, 0) to (0, 12) to (3

Serhud [2]

$C$ has a clockwise orientation, so in order to use Green's theorem (which is probably the "theorem" mentioned here), we have

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=-\iint_D\frac{\partial(xy+x\cos x)}{\partial x}-\frac{\partial(y\cos x-xy\sin x)}{\partial y}\,\mathrm dx\,\mathrm dy$

where $D$ is the triangle region.

$=\displaystyle\int_0^3\int_0^{12-4x}(\cos x-x\sin x)-(y+(\cos x-x\sin x))\,\mathrm dy\,\mathrm dx$

$=\displaystyle-\int_0^3\int_0^{12-4x}y\,\mathrm dy\,\mathrm dx=\boxed{-72}$

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3 years ago