Answer:
Approximately 55% of enrolled students are women.
Step-by-step explanation:
To find the percentage of a given set of data, you need to divide the number of actual students by the total number of students. In this case, they are wanting the percentage of just women students at the university:
x 100 = 55%
Answer: igewuuuuuuuuuuuuuuuuuuuuuuuuudh.j
Step-by-step explanation:
Answer:
6.25 % of area of Large triangle = area of smallest triangle
Step-by-step explanation:
Area of large triangle L = (1/2)*base*height
L = (1/2)*(44 m)* h
L = 22*h square m.
2nd equilateral triangle area: S =(1/2)*(22 m)*(0.5h)
S = 5.5*h sq. m.
3rd smallest equilateral triangle area : T = (1/2)*(11 m)*(0.25h)
T = 1.375*h sq. m
-----
Find percent P where T = P* L, 1.375*h = P * 22*h
P = 6.25% = 0.0625
Answer:
0.345
Step-by-step explanation:
Use binomial probability:
P = nCr pʳ qⁿ⁻ʳ
where n is the number of trials,
r is the number of successes,
p is the probability of success,
and q is the probability of failure (1−p).
n = 5, r = 2, p = 0.41, and q = 0.59.
P = ₅C₂ (0.41)² (0.59)⁵⁻²
P = 0.345
Answer:
2. The change in expected height for every one additional centimeter of femur length.
Step-by-step explanation:
<u>1. The expected height for someone with a femur length of 65 centimeters.</u>
<em>Doesn't make sense, that would be height value when centimeters = 65.</em>
<u>2</u><u><em>. </em></u><u>The change in expected height for every one additional centimeter of femur length.</u>
<em>Makes sense, for every increase in one additional centimeter, we can expect the height to be proportional to the slope.</em>
<u>3. The femur length for someone with an expected height of 2.5 centimeters.</u>
<em>Doesn't make sense, the linear relationship relies on the femur length to get the height.</em>
<u>4. The change in expected femur length for every one additional centimeter of height.</u>
<em>Doesn't make sense, again, the linear relationship relies on the femur length.</em>
