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3 years ago

How can you use the point-slope form of a line when only given two points?

Mathematics

1 answer:

pshichka [43]3 years ago

3 0

Answer:

See below

Step-by-step explanation:

<u>Point -slope form is:</u>

y - y1 = m(x - x1)

By having one set of coordinates and knowing the value of the slope (m in the equation) you can use the form.

<u>How to find the slope?</u>

Here you need 2 points: Point 1 with coordinates x1, y1 and point 2 with the coordinates x2, y2

<u>Use the formula:</u>

m = (y2-y1)/(x2-x1)

<u>Example:</u>

m = -5, and one of the points has coordinates (9, 2) then point-slope form is:

y - 2 = -5(x - 9)

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Answer:

1) n= 20.5

2) t= -17/3

Step-by-step explanation:

1) -4n + 20 = -62

-4n = -82

n = 20.5

2) -3t = 17

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2 years ago

Two numbers have theses properties . both numbers are greater than 6 . their hcf = 6 . their lcm = 60. what are the two numbers

aleksandrvk [35]

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x*y=HCF*LCM=6*60=360
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2 years ago

A ladder that is 13 meters long is leaning against a wall. The distance between the foot of the ladder and the wall is 7 meters

Maksim231197 [3]

<h2>Answer:</h2>

The equation that is used to model the length of ladder in terms of x is:

$x^2-7x-60=0$

<h2>Step-by-step explanation:</h2>

We can model this problem with the help of a right angled triangle whose hypotenuse is 13 meters and the other two legs are x meters and (x-7) meters.

where x is the distance between the top of the ladder and the ground.

and (x-7) is the distance between the foot of the ladder and the wall.

Hence, using Pythagorean Theorem we have:

$13^2=x^2+(x-7)^2\\\\i.e.\\\\169=x^2+x^2+49-14x\\\\i.e.\\\\169=2x^2-14x+49\\\\i.e.\\\\2x^2-14x+49-169=0\\\\i.e.\\\\2x^2-14x-120=0\\\\i.e.\\\\x^2-7x-60=0$

Hence, the answer is:

$x^2-7x-60=0$

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