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3 years ago

Which is more, 24 quarts or 7 gallons?

Mathematics

2 answers:

ludmilkaskok [199]3 years ago

5 0

Hey! 7 gallons is more because there are 6 gallons in 24 quarts and 6 is less then 7

kirill [66]3 years ago

5 0

Answer:

7 gallons is more because if in quarts it would be 28 quarts

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A line passes through the point (10,-8) and has a slope of -5/2. write an equation in point-slope form for this line.

Nady [450]

Answer:

y= -5/2 + 17

Step-by-step explanation:

y=mx+b

-8=-5/2(10)+b

-8=-25+b

17=b

y = -5/2x + 17

6 0

3 years ago

Really need help I don't understand

Mrrafil [7]

we know the circumference shown for that picture is π miles, what would it be for the diameter? namely how long is the diameter of that circle whose circumference is π miles?

$\bf \textit{circumference of a circle}\\\\ C=\pi d~~ \begin{cases} d=diameter\\ \cline{1-1} C=\pi \end{cases}\implies \pi =\pi d\implies \cfrac{~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=d\implies 1=d$

6 0

4 years ago

I’m not sure how to solve this. help?

shtirl [24]

Answer:

The measure of ∠GKH is 27°

Step-by-step explanation:

In the isosceles triangle, the base angles are equal in measures

The measure of an exterior angle at a vertex of a triangle equals the sum of the measures of two opposite interior angles

In Δ HJK

∵ HJ = JK

→ That means the triangle is isosceles

∴ Δ HJK is an isosceles triangle

∵ ∠JHK and ∠JKH are base angles

→ By using the first rule above

∴ m∠JHK = m∠JKH

∵ m∠HJK = 70°

∵ m∠JHK + m∠JKH + m∠HJK = 180° ⇒ interior angles of a triangle

∴ m∠JHK + m∠JKH + 70 =180

→ Subtract 70 from both sides

∴ m∠JHK + m∠JKH = 110

→ Divide their sum by 2 to find the measure of each one

∴ m∠JHK = m∠JKH = 110 ÷ 2 = 55°

∵ ∠JHK is an exterior angle of ΔGHK at vertex H

∵ ∠HGK and ∠GKH are the opposite interior angles to ∠JHK

→ By using the 2nd rule above

∴ m∠JHK = m∠HGK + m∠GKH

∵ m∠JHK = 55°

∵ m∠HGK = 28°

∴ 55 = 28 + m∠GKH

→ Subtract 28 from both sides

∴ 27° = m∠GKH

∴ The measure of ∠GKH is 27°

3 0

3 years ago

The position of a model train, in feet along a railroad track, is given by

miv72 [106K]

Answer:

Part a) The speed is $2.5\frac{ft}{sec}$

Part b) After 4 seconds the trains is 24 ft along the track

Part c) $t=6\ sec$

Step-by-step explanation:

we have

$s(t)=2.5t+14$

This is the equation of a line in slope intercept form

where

s(t) is the position of a model train in feet

t is the time in seconds

Part a) How fast is the train moving?

The speed of the train is equal to the slope of the linear equation so

The slope m is equal to

$m=2.5\frac{ft}{sec}$

therefore

The speed is $2.5\frac{ft}{sec}$

Part b) Where is the train after 4 seconds?

For t=4 sec

substitute the value of t in the equation and solve for s

$s(4)=2.5(4)+14=24\ ft$

therefore

After 4 seconds the trains is 24 ft along the track

Part c) When will the train be 29 feet along the track?

For s(t)=29 ft

Substitute the value of s(t) in the equation and solve for t

$29=2.5t+14$

subtract 14 both sides

$29-14=2.5t$

$15=2.5t$

Divide by 2.5 both sides

$6=t$

rewrite

$t=6\ sec$

3 0

3 years ago

What is the error in this problem

castortr0y [4]

Answer:

12). LM = 37.1 units

13). c = 4.6 mi

Step-by-step explanation:

12). LM² = 23² + 20² - 2(23)(20)cos(119)°

LM² = 529 + 400 - 920cos(119)°

LM² = 929 - 920cos(119)°

LM = $\sqrt{929+446.03}$

= $\sqrt{1375.03}$

= 37.08

≈ 37.1 units

13). c² = 5.4² + 3.6² - 2(5.4)(3.6)cos(58)°

c² = 29.16 + 12.96 - 38.88cos(58)°

c² = 42.12 - 38.88cos(58)°

c = $\sqrt{42.12-20.603}$

c = $\sqrt{21.517}$

c = 4.6386

c ≈ 4.6 mi

3 0

3 years ago