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liq [111]
3 years ago
11

Which is more, 24 quarts or 7 gallons?

Mathematics
2 answers:
ludmilkaskok [199]3 years ago
5 0
Hey! 7 gallons is more because there are 6 gallons in 24 quarts and 6 is less then 7
kirill [66]3 years ago
5 0

Answer:

7 gallons is more because if in quarts it would be 28 quarts

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Please answer the following 4 questions
Lilit [14]
1. The correct answer should be A
2. The answer should be C
3. I think the answer is D
4. The answer should be D


Hope this helps :)
7 0
3 years ago
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Solve the following congruence equations for X a) 8x = 1(mod 13) b) 8x = 4(mod 13) c) 99x = 5(mod 13)
xxMikexx [17]

Answer:

a) 5+13k  where k is integer

b) 20+13k where k is integer

c)12+13k where k is integer

Step-by-step explanation:

(a)

8x \equiv 1 (mod 13) \text{ means } 8x-1=13k.

8x-1=13k

Subtract 13k on both sides:

8x-13k-1=0

Add 1 on both sides:

8x-13k=1

I'm going to use Euclidean Algorithm.

13=8(1)+5

8=5(1)+3

5=3(1)+2

3=2(1)+1

Now backwards through the equations:

3-2=1

3-(5-3)=1

3-5+3=1

(8-5)-5+(8-5)=1

2(8)-3(5)=1

2(8)-3(13-8)=1

5(8)-3(13)=1

So compare this to:

8x-13k=1

We see that x is 5 while k is 3.

Anyways 5 is a solution or 5+13k is a solution where k is an integer.

b)

8x \equiv 4 (mod 13)

8x-4=13k

Subtract 13k on both sides:

8x-13k-4=0

Add 4 on both sides:

8x-13k=4

We got this from above:

5(8)-3(13)=1

If we multiply both sides by 4 we get:

8(20)-13(12)=4

So x=20 and 20+13k is also a solution where k is an integer.

c)

[tex]99x \equiv 5 (mod 13)[/tex

99x-5=13k

Subtract 13k on both sides:

99x-13k-5=0

Add 5 on both sides:

99x-13k=5

Using Euclidean Algorithm:

99=13(7)+8

13=8(1)+5

Go back through the equations:

13-8=5

13-(99-13(7))=5

8(13)-99=5

99(-1)+8(13)=5

Compare this to 99x-13k=5 and see that x=-1 or -1+13=12 or 12+13k is a solution where k is an integer.

8 0
3 years ago
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The time that a butterfly lives after emerging from its chrysalis can be modelled by a random variable T, the model here taking
olasank [31]
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8 0
3 years ago
What is 5^3 x 5^11 <br> im so lost
Ne4ueva [31]

Answer:

5^(14)

Step-by-step explanation:

5^3 x 5^11

We know that a^b * a^c = a^(b+c)

5^3 x 5^11 = 5^(3+11) = 5^(14)

3 0
3 years ago
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Sam practices his guitar for 9 hours each week he practices each song for 3 1/2 hours. What is the greatest number of song he ca
liberstina [14]

Answer:

<em>The greatest number of song he can practice in a week is  2.</em>

Step-by-step explanation:

Suppose, the greatest number of song he can practice in a week is  x

He practices each song for 3\frac{1}{2} hours. So, the total time required for practicing x number of songs = (3\frac{1}{2}*x) hours.

Given that, he practices his guitar for 9 hours each week.

So, the equation will be......

3\frac{1}{2}*x= 9\\ \\ x= 9\div 3\frac{1}{2}\\ \\ x=9\div \frac{7}{2}=9 \times \frac{2}{7}=\frac{18}{7}= 2.571.... \approx 2

<em>(Rounded as the greatest whole number)</em>

Thus, the greatest number of song he can practice in a week is  2.

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3 years ago
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