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2. 0 mc charge in an external field of 20n/c, north (direction) will experience a force of 0.4 newtons, the direction of the force is north
Force in an electric field = charge * electric field
given
charge = 2* C
electric field = 20 N/C
Force in an electric field = 2* * 20
= 0.04 N
since , external field is in north direction then the force must be in north direction because the direction of an electric field at a point is the same as the direction of the electric force acting on a positive test charge
hence, 2. 0 mc charge in an external field of 20n/c, north (direction) will experience a force of 0.4 newtons, the direction of the force is north
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Answer:
The time is 5.71 sec.
Explanation:
Given that,
Acceleration
Initial velocity = 24.0 m/s
We need to calculate the time
Using equation of motion
v = u+at[/tex]
Where, v = final velocity
u = inital velocity
t = time
a = acceleration
Put the value into the formula
Hence, The time is 5.71 sec.