Answer:
second option: (4, 4) is the solution to both lines A and B.
Step-by-step explanation:
You know that the equation of line A is:
and the equation of line B is:
The point in which the line A intersects with the line B is the solution of the sytstem of equations.
You can observe in given graph that the point of intersection of Line A and Line B is: (4,4)
Therefore (4, 4) is the solution to both lines A and B.
Answer:
y= 1 and x=-2
Step-by-step explanation:
Since they both equal y, you can equal them to each other:
x + 3 = 2x + 5
Then solve:
x - x + 3 = 2x - x + 5
3 - 5 = x + 5 - 5
-2 = x
Substitute x in either equation to solve for y:
y = (-2) +3
y = 1
Or the other equation:
y = 2(-2) + 5
y = -4 + 5
y = 1
hope this helps :)
Let the width =x
length = 6x
p=14x
28=14x
x=2
In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.
So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.
x + 1.5 = 14
x = 12.5 ounces
The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces
x + 1.5 = 16
x = 14.5 ounces
From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
