Help me I need help please anyone

Mathematics

1 answer:

jarptica [38.1K]3 years ago

7 0

Answer:

1st,4th,5th option.

Step-by-step explanation:

Let evaluate each option.

A segment bisector is a line segment, ray, and/or line that bisects a line into two congruent parts. LM splits JK and KH into congruent parts. The first option is correct.

A perpendicular bisector is a line segment,ray and/or line that intersects a line segment,ray at a right angle. We don't have a perpendicular angle here and so that isn't a option.

M isn't a vertex of congruent angles as there is none in this figure.

The fourth and fifth option are correct. They both are on the segment bisector so they split the figure segments into two congruent parts. Since they are on the line segment and bisects it, they are considered the midpoint or middle point of the figure side.

You might be interested in

Solve the equation for x. −3=x3−6<br> A. x=−27<br> B. x=9<br> C. x=0<br> D. x=−6

Soloha48 [4]

Umm I think it would be C all thought I got 1 when doing the work

6 0

3 years ago

Suppose that 1 month before the election a random sample of 500 registered voters are surveyed. From this sample 270 indicate th

Aleonysh [2.5K]

Answer:

[ 0.4964, 0.5836 ]

Step-by-step explanation:

Data provided in the question:

Total sample size = 500

person voting for smith = 270

thus,

P( person voting for smith ), p = $\frac{270}{500}$ = 0.54

Confidence level = 95%

now,

standard error, SE = $\sqrt{\frac{p(1-p)}{n}$

SE = $\sqrt{\frac{0.54(1-0.54)}{500}$

SE = 0.0223

now,

Confidence interval = p ± ( z × SE )

here,

z value for 95% confidence interval is 1.96

Confidence interval = [ 0.54 - ( 1.96 × 0.0223 ), 0.54 + ( 1.96 × 0.0223 ) ]

= [ 0.54 - 0.0436 , 0.54 + 0.0436 ]

= [ 0.4964, 0.5836 ]

8 0

3 years ago

Find A ∩ B if A = {2, 5, 8, 11, 14} and B = {1, 3, 5, 7}.

Gwar [14]

Answer:

Step-by-step explanation:

$A=\{2,\ 5,\ 8,\ 11,\ 14\}\\\\B=\{1,\ 3,\ 5,\ 7\}\\\\A\ \cap\ B-\text{the intersection of two sets A and B,}\\\text{ is the set that contains all elements of A that also belong to B.}\\\\\text{Therefore:}\ A\ \cap\ B=\{5\}$