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klemol [59]
2 years ago
15

Help me I need help please anyone

Mathematics
1 answer:
jarptica [38.1K]2 years ago
7 0

Answer:

1st,4th,5th option.

Step-by-step explanation:

Let evaluate each option.

A segment bisector is a line segment, ray, and/or line that bisects a line into two congruent parts. LM splits JK and KH into congruent parts. The first option is correct.

A perpendicular bisector is a line segment,ray and/or line that intersects a line segment,ray at a right angle. We don't have a perpendicular angle here and so that isn't a option.

M isn't a vertex of congruent angles as there is none in this figure.

The fourth and fifth option are correct. They both are on the segment bisector so they split the figure segments into two congruent parts. Since they are on the line segment and bisects it, they are considered the midpoint or middle point of the figure side.

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Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2  = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.

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