Help me I need help please anyone

Mathematics

1 answer:

jarptica [38.1K]2 years ago

7 0

Answer:

1st,4th,5th option.

Step-by-step explanation:

Let evaluate each option.

A segment bisector is a line segment, ray, and/or line that bisects a line into two congruent parts. LM splits JK and KH into congruent parts. The first option is correct.

A perpendicular bisector is a line segment,ray and/or line that intersects a line segment,ray at a right angle. We don't have a perpendicular angle here and so that isn't a option.

M isn't a vertex of congruent angles as there is none in this figure.

The fourth and fifth option are correct. They both are on the segment bisector so they split the figure segments into two congruent parts. Since they are on the line segment and bisects it, they are considered the midpoint or middle point of the figure side.

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The table shows the values of a function f(x).

QveST [7]

Answer:

The average rate of change is $=-4$

Step-by-step explanation:

The average rate of change from x=a to x=b of f(x) is given by;

$=\frac{f(b)-f(a)}{b-a}$

We want to find the average rate of change of the function represented in the table from x=-2 to x=2.

$=\frac{f(2)-f(-2)}{2--2}$

From the table f(-2)=25 and f(2)=9

The average rate of change from x=-2 to x=2 is

$=\frac{9-25}{2--2}$

$=\frac{-16}{4}$

$=-4$

3 0

3 years ago

Will award brainliest to correct answer!

Artyom0805 [142]

Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

$\angle \: ABP = \frac{180 - 80}{2} = 50 \degree$

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.

Therefore, the angle BKQ is equal to 180-50-45=85°.

Of course angle BKP=180-85=95°.

Hope this helps :)

6 0

2 years ago

Solve using square roots 3x^2+25=73

seropon [69]

Heya !

Given expression -

$3 {x}^{2} + 25 = 73$

Subtracting 25 both sides ,

$3 {x}^{2} + 25 - 25 = 73 - 25 \\ \\ 3 {x}^{2} = 48$

Dividing by 3 on both sides ,

$\frac{3 {x}^{2} }{3} = \frac{48}{3} \\ \\ {x}^{2} = 16$

Therefore ,
$x = + \: 4 \: \: \: \: or \: \: - 4 \: \: \: \: \: \: \: Ans.$