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irina1246 [14]
3 years ago
12

Can u PLEASE help with problem 3. and 4. (ONLY IF YOU KNOW)

Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0
It would help if we were able to see the previous exercises to help you with these.
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What is the slope of the line that passes through (-2,-2) and (3,-1)?
JulsSmile [24]

Answer:

+1/5

Step-by-step explanation:

3 0
3 years ago
Look at the image. ( Ill give brainliest to best answer.)
nalin [4]
C. 1 solution hope it helps
3 0
3 years ago
The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

6 0
3 years ago
the volume V of a gas at a constant temperature varies inversely with the pressure P. when the volume is 100 cubic inches the pr
fiasKO [112]

Answer:

The pressure is 20\ psi

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form y*x=k or y=k/x

In this problem we have

V*P=k

where

V is the volume of a gas at a constant temperature

P is the pressure

we have

For V=100\ in^{3},P=25\ psi

step 1

Find the value of k

substitute the values of V and P

100*25=k

k=2,500

The equation is equal to  V*P=2,500

step 2

Find the pressure when the volume is 125 cubic inches

For V=125\ in^{3}

substitute in the equation and solve for P

125*P=2,500

P=2,500/125=20\ psi

8 0
3 years ago
Write an equation of a line that is perpendicular to the given line and that passes through the given point.
devlian [24]
Here is the answer I believe. It goes in a x all it did was added to to each x and y (-3,0)
8 0
3 years ago
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