Answer:
(1, 3 )
Step-by-step explanation:
Substitute x = 1 into the equation
y = 
× 
= × 6 = 3
(1, 3 ) ← with output value y = 3
Step-by-step explanation:
(q and (not q or p)) = (q and not q) or (q and p) = false or q and p = q and p
(p and not (q and p)) = (p and (not q or not p)) =
= (p and not q) or (p and not p) = (p and not q) or false =
= p and not q
so, we have in total
(q and p) or (p and not q) = (p and q) or (p and not q).
this is p, because if p=false both brackets are false and therefore the whole expression is false. and if p=true, then one of the 2 brackets must be true, which makes the whole expression true.
Applying BODMAS (Order of operations rule)
Where: B is for brackets
O is for 'of' which means multiplication
D is for division
M is for multiplication
A is for addition
S is for subtraction
<u>In this case:</u>
We start with addition then we go to addition and finally we subtract.
(78 × 13) - (8 × 78) + (26 × 78) - 78
= 1014 - 624 + 2028 - 78
= 1014 + 2028 - 624 - 78
= 3042 - 624 - 78
=2340
