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Nata [24]
3 years ago
15

If y is 9 and x is 12, what additional information is necessary to show that triangle DUM is congruent to triangle MAP using the

SAS postulate?

Mathematics
1 answer:
Law Incorporation [45]3 years ago
6 0
                         Δ DUM         Δ MAP

hypotenuse:      15                2y-3
short leg:             12                0.5x + 6

y = 9 ⇒ 2(9) - 3 = 18 - 3 = 15 Congruent with the hypotenuse of Δ DUM
x = 12 ⇒ 0.5(12) + 6 = 6 + 6 = 12 Congruent with the short leg of Δ DUM

SAS postulate states that two triangles are congruent if 2 of its sides and 1 angle have equal measure. Both the hypotenuse and short leg are equal in measure. Thus, both triangles are congruent with each other.
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The model represents an equation.
madreJ [45]

Answer:

9/5

Step-by-step explanation:

solve the original equation for x

-4× + 3 = 1x +(-6)

-1x

-5x + 3 = -6

-3

-5x = -9

/-5

x = 9/5

CHECK

-4(9/5) + 3 = 1(9/5) +(-6)

-21/5 = -21/5

8 0
2 years ago
Bert measured a swimming pool and made a scale drawing. The scale of the drawing was
Cerrena [4.2K]
1/100
Each meter is 100 centimeter
8 0
3 years ago
What is the sum of the geometric series
Sergio039 [100]
Answer: 2343 / 256

Explanation

I will do this for you in two forms: 1) adding each term, and 2) using the general formula for the sum of geometric series.

1) Adding the terms:

 4
∑ 3 (3/4)^i = 3 (3/4)^0 + 3 (3/4)^1 + 3 (3/4)^2 + 3 (3/4)^3 + 3 (3/4)^4
i=0

= 3 + 9/4 + 27/16 + 81/64 + 243/256 = [256*3 + 27*16 + 64*9 + 4*81 + 243] / 256 =

= 2343 / 256

2) Using the formula:

n-1
∑ A (r^i) = A [1 - r^(n) ] / [ 1 - r]
i=0

Here n - 1 = 4 => n = 5

r = 3/4

A = 3

Therefore the sum is 3 [ 1 - (3/4)^5 ] / [ 1 - (3/4) ] =

= 3 [ 1 - (3^5) / (4^5) ] / [ 1/4 ] = 3 { [ (4^5) - (3^5) ] / (4^5) } / {1/4} =

= (3 * 781) / (4^5) / (1/4) =  3 * 781 / (4^4) = 2343 / 256

So, no doubt, the answer is 2343 / 256
5 0
3 years ago
Given: x - 8 > -3.
Vera_Pavlovna [14]

Answer:

x-8>-3 {x|R, x>5 is right answer

5 0
3 years ago
Read 2 more answers
Plz Helppp meeee assapppp
Gwar [14]

Given:

A right angled triangle.

To find:

The value of x.

Solution:

We have,

Base = x

Hypotenuse = \sqrt{5}

In a right angle triangle,

\cos \theta = \dfrac{Base}{Hypotenuse}

For the given triangle,

\cos 45^\circ= \dfrac{x}{\sqrt{5}}

\dfrac{1}{\sqrt{2}}= \dfrac{x}{\sqrt{5}}

Multiply both sides by \sqrt{5}.

\dfrac{\sqrt{5}}{\sqrt{2}}= x

\dfrac{\sqrt{5}}{\sqrt{2}}\times \dfrac{\sqrt{2}}{\sqrt{2}}= x

\dfrac{\sqrt{10}}{2}= x

Therefore, the required value of x is \dfrac{\sqrt{10}}{2}.

8 0
2 years ago
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