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GaryK [48]
3 years ago
6

Evaluate. log(3)5 = _____ 0.68 1.46 0.60

Mathematics
1 answer:
Rom4ik [11]3 years ago
4 0

By using the base change formula, which states

\log _{a}b= \frac{\log b}{\log a}

The given equation is \log _{3}5= \frac{\log 5}{\log 3}

By substituting the values of log 5 and log 3.

= \frac{0.6989}{0.477}

= 1.46

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a woman 1.65. tall stood 50m away from the foot of a tower,and observe that the angle of elevation of the top of the tower to be
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\sf\huge\underline{\star Solution:-}

\rightarrowLet the women's height be AE and distance between the women and tower be AC.

Also let the height of tower be BC.

\rightarrowNow, clearly it is forming a triangle.

So, in triangle ABC,

\rightarrow\sf{Tan50° \:= \: \frac{BC}{AC}}

\rightarrow\sf{1.19 \:= \: \frac{BC}{50}}

\rightarrow\sf{1.19 ×50\:= \: BC}

\rightarrow\sf{59.5m\:= \: BC}

\rightarrowHence, BC = 59.5m

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Therefore, total height of the tower =\sf\purple{ 61.15m.}

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2 years ago
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