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3 years ago

Which data would be best analyzed and communicated using a histogram

1 answer:

4 0

The data with one same characteristic, different number and comparable would be best analyzed and communicated using a histogram. For example, one gene expression in different tissues or different samples.

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How many days are in one year on Earth? Do all planets in our solar system have the same number of days in one year? What determ

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Explanation: I think this is the answer I’m not too sure though !

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3 years ago

Is natural gas found in equal amounts around the globe? Why or why not?

Masja [62]

No, it's found in many different amounts. It's obvious that you find different amounts of it in different places that you go.

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3 years ago

When a perfume bottle is opened, some liquid changes to gas and the fragrance spreads around the room

julia-pushkina [17]

I'm sorry but I need a little bit more context

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3 years ago

Rutherford tracked the motion of tiny, positively charged particles shot through a thin sheet of gold foil. Some particles trave

Amiraneli [1.4K]

Answer:

Some particles traveled through empty parts of the atom and some particles were deflected by small areas of high-density positive charge in atoms.

Explanation:

In Rutherford's experiment, the particles either traveled straight through the gold foil or were deflected by the positively charged nucleus.

So, this answer is correct because the particles traveled through empty parts of the atom (not empty spaces between atoms) and some particles were deflected by areas of high-density positive charge (the nucleus).

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4 years ago

Read 2 more answers

In mice, black coat color (B) is dominant over brown (b), and a solid pattern (S) is dominant over white spotted (s). Color and

jenyasd209 [6]

Answer and Explanation:

It is a dihybrid cross, where:

B= black (dominant)

b= brown

S= solid (dominant)

s= spotted

a) The genotype of the parents are:

homozygous black spotted= BBss ⇒ Gametes: Bs, Bs, bS, bS

homozygous brown solid= bbSS ⇒ Gametes: bs, bs, bs, bs

The F1 mice is the resultant progeny from the cross BBss x bbSS. We combine the games of the parents and all combinations are : BbSs. All F1 genotype is BbSs (heterozygous black and solid mice).

b) The testcross is carried out between F1 mice (BbSs) and brown spotted mice (bbss)

BsSs ⇒ Gametes: BS, Bs, bS, bs

bbss ⇒ Gametes: bs, bs, bs, bs

From the gametes, we obtain all the possible combinations:

BSbs = BbSs (black, solid) ⇒ ratio= 1/2 x 1/2= 1/4

Bsbs= Bbss (black, spotted) ⇒ ratio= 1/2 x 1/2= 1/4

bSbs= bbSs (brown solid) ⇒ ratio= 1/2 x 1/2= 1/4

bsbs= bbss (brown spotted) ⇒ ratio= 1/2 x 1/2= 1/4

So, we obtain 1/4 of black solid mice (BbSs), 1/4 of black spotted mice (Bbss), 1/4 of brown solid mice (bbSs) and 1/4 of brown spotted mice (bbss).

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3 years ago