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drek231 [11]
3 years ago
9

How many protons are in Si-28

Chemistry
1 answer:
vladimir1956 [14]3 years ago
5 0
In the isotope of Si-28, there are 14 protons.
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Which of the compounds in the table below is listed in the wrong colum?
Sveta_85 [38]

Answer: C

Explanation: This is because of a nice thing called guessing

5 0
3 years ago
What equation do you use to go from mass to mole?
liq [111]

Answer:

Number of moles = mass/molar mass

Explanation:

Given data:

mass of Al = 11 g

Moles = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of aluminium is 27 g/mol

Now we will put the values in formula.

Number of moles = 11 g/ 27 g/mol

Number of moles = 0.41

The number of moles in 11 g Al are 0.41 mol.

5 0
3 years ago
A class of substances known as __________ are used for their medicinal properties.
Misha Larkins [42]

Answer: Alkaloids

A class of substances known as alkaloids are used for their medicinal properties.

Explanation:

Alkaloids are small but complex organic substances with at least one nitrogen atom in its ring structure. Hence, they have strong basic properties, and are produced in naturally by some plants.

Examples of alkaloids and their medicinal properties are as follows:

- caffeine, used in certain drug and drinks to stimulate the nervous system

- morphine, used to reduce pain and induce sleep in humans.

- cocaine, nicotine etc

6 0
3 years ago
Read 2 more answers
2. What charge does an electron have? a. Positive b. Negative c. Neutral d. No charge
SashulF [63]
The answer is negative, since neutron is neutral and Protons have Positive.
7 0
3 years ago
Find the ΔH for the reaction below, given the following reactions and subsequent ΔH values: PCl5(g) → PCl3(g) + Cl2(g)
nalin [4]

Answer:

The value of \Delta H for the desired reaction will be 249.75 KJ.

Explanation:

The desired reaction is shown below

\textrm{PCl}_{5}\left ( g \right )\rightarrow \textrm{PCl}_{3}\left ( g \right )+\textrm{Cl}_{2}\left ( g \right )

The desired reaction can be obtained by adding the given reactions and then dividing both sides by 4.

P_{4}\left ( s \right )+6Cl_{2}\left ( g \right )\rightarrow 4PCl_{3}\left ( g \right ) \\4PCl_{5}\left ( g \right )\rightarrow P_{4}\left ( s \right )+10Cl_{2}\left ( g \right )

Net Enthalpy change for the desired reaction

\displaystyle \frac{3438-2439}{4} \textrm{ KJ} = 249.75 \textrm{ KJ}

\Delta H = 249.75 \textrm{ KJ}

6 0
4 years ago
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