<h2>Let us solve for it </h2>
Explanation:
Magnesium oxide
- It is MgO
- Its molecular mass is : 24 +16=40 g
- When MgO decomposes it forms = 3.54 g of oxygen gas
- when 40 g of MgO decomposes it forms = 16g of oxygen
- or we can say that :
- 16g of oxygen is produced when 40 g of MgO is decomposed .
- 1g of oxygen will be formed from =40/16g of MgO
- 3.54 g of oxygen will be formed = 40/16 x 3.54 =8.85g of MgO
Chemical equation represents a redox reaction :
2Li + MgCl₂ → 2LiCl + Mg
<h3>Further explanation</h3>
The oxidation-reduction reaction or abbreviated as Redox is a chemical reaction in which there is a change in oxidation number
Reaction
2Li + MgCl₂ → 2LiCl + Mg
Oxidation is an increase in oxidation number, while reduction is a decrease in oxidation number.
Oxidation
Reduction
The solubility of potassium chloride in at room temperature is approximately 34 g per 100 g of water. Therefore, the maximum amount that could be dissolved would be 34/100 ( 200) = 68 g of KCl. When more than this amount is added, excess potassium would not dissolve forming crystals in the solution.
Answer is: the equilibrium concentrations fluorine anion are 0.004 M and lead cation are 0.002 M.<span>
Chemical reaction: PbF</span>₂(aq) → Pb²⁺(aq) + 2F⁻(aq).<span>
Ksp = 3,2·10</span>⁻⁸.
[Pb²⁺] = x.
[F⁻] = 2[Pb²⁺] = 2x<span>
Ksp = [Pb²</span>⁺] ·
[F⁻]².
Ksp = x · 4x².
3,2·10⁻⁸ = 4x³.
x = ∛3,2·10⁻⁸ ÷ 4.
x = [Pb²⁺] = 0,002M = 2·10⁻³ M.
[F⁻] = 2 · 0,002M = 0,004 M = 4·10⁻³ M.
Answer:
Iron
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