You can use grams to moles and moles to grams. In your case just grams to moles. So since you're given grams, you would divide that by the molar mass of CO2 because that's how many grams are in one mole. The mass for Carbon is 12.0104 g/mol and Oxygen it's 15.9994 g/mol so to find the molar mass you would add 12.0104 + (2*15.9994) which gives you a molar mass of 44.0095 g/mol. You divide your given mass (132g) by the molar mass, so there's 2.9993 moles or approximately 3 moles in 132 g of CO2.
Answer:
Periods on the periodic table of elements
Explanation:
In the periodic table of elements, there are seven horizontal rows of elements called periods. The vertical columns of elements are called groups, or families. (See also The Periodic Table: Metals, Nonmetals, and Metalloids.) In each period (horizontal row), the atomic numbers increase from left to right.
Answer:
1.62x10⁻³ moles of NaOH were dispensed
Explanation:
Molarity is an unit in chemistry defined as the ratio between moles of solute (In the problem, NaOH), per liter of solution.
The concentration of the solution is 0.125moles per liter. That means 1L of solution has 0.125 moles of NaOH.
The volume you dispensed in the buret was:
15.67mL - 2.73mL =
12.94mL of the 0.125M NaOH are:
12.94mL = 0.01294L * (0.125moles / L) =
<h3>1.62x10⁻³ moles of NaOH were dispensed</h3>
Options are as follow,
A) <span>Constant volume, no intermolecular forces of attraction,energy loss in collisions
B) </span><span>No volume, strong intermolecular forces of attraction, perfectly elastic collisions
C) </span><span>Constant volume, no intermolecular forces of attraction, energy gain during collisions
D) </span><span>No volume, no intermolecular forces of attraction, perfectly elastic collisions
Answer:
Option-D (</span>No volume, no intermolecular forces of attraction, perfectly elastic collisions) is the correct answer.
Explanation:
As we know there are no interactions between gas molecules due to which they lack shape and volume and occupies the shape and volume of container in which they are kept. So, we can skip Option-B.
Secondly we also know that the gas molecules move randomly. They collide with the walls of container causing pressure and collide with each other. And these collisions are perfectly elastic and no energy is lost or gained during collisions. Therefore Option-A and C are skipped.
Now we are left with only Option-D, In option D it is given that ideal gas has no volume. This is true related to Ideal gas as it is stated in ideal gas theories that molecules are far apart from each other and the actual volume of gas molecules compared to volume of container is negligible. Hence, for ideal gas Option-D is a correct answer.
