Derived from a 6 membered ring. Contains Cytosine, Thymine, and Uracil.
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<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2><h2>Phenotype:</h2>
It is the physical appearance of the trait, whether the person has smooth chin or cleft chin.
<h2>Genotype:</h2>A genotype refers to the genetic characteristics of an organism's trait, if it is heterozygous or hom.ozygous, recessive or dominant.
<h2>_____________________________________</h2><h2>Alleles:</h2>Cleft chin C is dominant over smooth chin c
<h2>Genotypes of Parents:</h2><h3>FATHER:</h3>Father has smooth chin thus, it is hom.ozygous recessive i.e. cc
<h3>MOTHER:</h3>Mother has cleft chin, since cleft chin is dominant there are two possibilities of her genotype,
Heterozygous Dominant : Cc
Hom.zygous Dominant : CC
but if we cross the hom.zygous fominant mother to hom.ozygous recessive father we will get all the offsprings with the same genotype phenotype so it is not possibile, So the mother is HETEROZYGOUS DOMINANT Cc
<h2>_____________________________________</h2><h2><u>Question</u>:</h2><h2>_____________________________________</h2><h2>Genotypes of Parents:</h2>FATHER: cc (Hom.ozygous Recessive)
MOTHER: Cc (Heterozygous Dominant)
<h2>_____________________________________</h2><h2>Punnet Square:</h2>Picture attached!
Picture no 1: it is the cross between hom.ozygous recessive father and hom.ozygous dominant mother and all the offsprings are same both phenotypic and genotypic way so IT IS NOT POSSIBILE
Picture no 2: Its cross between hom.ozygous recessive father and heterozygous dominant mother and there are hybrid and pure recessive both type of offsprings present thus IT IS POSSIBLE!
<h2>_____________________________________</h2><h2>Genotype Ratio of the Offspring:</h2>Hybrid : Pure Recessive
2 : 2 or 1 : 1
<h2>_____________________________________</h2><h2>Phenotype Ratio of the Offspring:</h2>Cleft Chin : Smooth Chin
2 : 2 or 1 : 1
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />