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GarryVolchara [31]
4 years ago
11

Why is it not possible to form a right triangle with the lengths 2, 4 and 7?

Mathematics
1 answer:
elixir [45]4 years ago
4 0

Answer:

It is not possible to form *any* triangle from the lengths 2, 4, and 7. The two short sides don't add to a length at least as long as the long side.

Step-by-step explanation:

I took the test. Hope this helps!

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What is C=24x+80 R=44x breakeven point
MA_775_DIABLO [31]
For this case we have the following equations:
 C = 24x + 80

 R = 44x
 The break even point occur when C = R:
 We have then:
 24x + 80 = 44x

 Clearing x we have:
 44x - 24x = 80

 20x = 80

 x = 80/20

 x = 4
 Then, substituting in any of the equations we have:
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 C = 96 + 80

 C = 176
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 Answer:
 
The break even point is:
 
(4, 176)
3 0
4 years ago
Follow the directions to solve the system of equations by elimination. 8x + 7y = 39 4x – 14y = –68 Multiply the first equation t
g100num [7]

Answer:

x=0.5 and y=5

Step-by-step explanation:

8x+7y=39...eqn(1)×-14

4x-14y=-68...eqn(2)×7

we now have,

-112x-98y=-546

-(28x-98y=-476)

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x=0.5

to solve for y, we substitute (x=0.5) into eqn (1) or eqn 2 which ever you want...

so I'm using eqn 1.

8x+7y=39

8(0.5)+7y=39

7y=39-4

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y=5

therefore, x=0.5, y=5

proof: substitute both x and y values to get you the same answer as the original solutions in both equations.

we have,

8(0.5)+7(5)=39

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4 0
4 years ago
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3 years ago
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Answer:

maths

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7 0
3 years ago
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Help with questions, I don't care if you google it
frutty [35]
Question 1:

7.488*10^{-8}÷3.12*10^{2}

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