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kaheart [24]
3 years ago
8

Help me please i need help with this

Mathematics
1 answer:
solmaris [256]3 years ago
7 0
(2x +y)(5x-y+3)

10x^2 - 2xy + 6x + 5xy - y^2 + 3y

10x^2 -2xy+5xy + 6x - y^2 + 3y
 
10x^2 +3xy + 6x -y^2 +3y        

Looking at the answer boxes the sign looks wrong to me from y^2 ( a negative times a positive is a negative) I may be wrong. 

Anyone else?
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Please help me! I need this answered fast!
Sonja [21]

Answer:

1. I think it's A.

2. I think it's D

8 0
3 years ago
Plz help me thank you!!!!!!
damaskus [11]

Answer:

h = 9.674

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The experimental factor that is manipulated; the variable whose effect is being studied is called ____________
lorasvet [3.4K]

Answer:

The experimental factor that is manipulated; the variable whose effect is being studied is called <u>independent variable.</u>

Step-by-step explanation:

Consider the provided information.

In an experiment, the two principal variables are the independent and dependent variable.

An independent variable is the variable that is altered or controlled to test the effects on the dependent variable in a scientific experiment.

The variable which is tested and measured in a scientific experiment is a dependent variable.

From the above definition: The experimental factor that changed or controlled in a scientific experiment is called independent variable.

Therefore, the complete statement is: The experimental factor that is manipulated; the variable whose effect is being studied is called <u>independent variable.</u>

8 0
3 years ago
Which of the sets of ordered pairs represents a function?
IgorC [24]

Answer:

Neither set A nor set B represents a function.  

Step-by-step explanation:

According to the definition of a function, for each input there exists a unique output. In other word for each value of x there exists unique value of y.

In set A we have four ordered pair (-4,5),(1,-1),(2,-2) and (2,3).

It means for x=2, we have two values of y, i.e., -2 and 3.

Since for a single value of x there exist more than one value of y, therefore set A is not a function.

In set B we have four ordered pair (2,2),(3,-2),(9,3) and (9,-3).

It means for x=9, we have two values of y, i.e., -3 and 3.

Since for a single value of x there exist more than one value of y, therefore set B is not a function.

3 0
3 years ago
Read 2 more answers
Find the k, in (2x^2 - 3x + k)/ x-4
amid [387]
Answer could be this 2x^2 - 7x + k/ x in a fraction with x being the only thing at the bottom btw
7 0
3 years ago
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