Question

In the equation 3x+9=27 how to solve?

Answer 1

The rule to solving these is to get x on its own by performing 'operations'. However, whatever we do the left-hand side we must also do to the right hand side. So,

$3x+9=27$, firstly that +9 is messing up the x so we take away 9 from the left to get rid of it but also take away 9 on the right because we have to.

$3x+9-9=27-9 \Rightarrow 3x=18$, next see that the 'times 3' is messing up the x so we divide the left-hand side by 3 to get rid but then also divide the right hand side because we have to.

$3x \div3=18\div 3 \Rightarrow x=6$ and then you have your solution.

Questions like this are all about figuring how to get the x on it's own but also remembering to do whatever you do on BOTH sides of the equals. Hope this helps.

Answer 2

Hey there! :D

3x+9= 27

Since 9 is being added, you subtract it from both sides. 

3x+9 (-9)= 27(-9)

3x= 18

Divide both sides by 3, since 3 is being multiplied by x.

x=6

I hope this helps!
~kaikers