Answer: Solution 2 because the single substrate easily get transformed into products at the active site of any of the 100 enzymes.
Explanation:
Since Solution 1 has 1 enzyme to 100 substrate while Solution 2 has 100 enzyme to 1 substrate, catalysis of the single substrate to product will be greater in Solution 2 as the enzyme will compete to quickly transform the single substrate in its active site unlike solution 1 will 100 substrates taking more time.
C and D can be ruled out since Dominant and Recessive refer to the alleles, not the offspring. Since the parents supplied different alleles to their offspring, the offspring would be heterozygous (hetero- means different, homo- means same).
The 2 phases are Prophase and Telophase
