What is the genotype of both parents?
1 answer:
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Answer: The genotype ratio is 2Ff : 2ff
The phenotype ratio is two normal feathered birds to two silky feathered birds.
Explanation: Let F represent the gene for normal feather and f represent the gene for silky feather. F is dominant while f is recessive, therefore a male that is hybrid for trait of normal feather is heterozygous and will have a genotype of Ff, a female that is homozygous for silky feather will have a genotype of ff.
A cross between Ff and ff will yield 2Ff birds and 2ff birds. Since F is dominant, a bird having genotype of Ff will manifest outwardly as blue feathered birds while ff will manifest outwardly as silky feathered birds because f is recessive and must occur in a homozygous condition in order to manifest phenotypically. Therefore, the genotype ratio is 2Ff: 2ff.
See the punnett square attached for more information
Answer: 25% of the offsprings will be heterozygous for both traits
Explanation: A cross between BbFf and bbff will yield 16 offsprings with four different possible genotypes: BbFf, Bbff, bbFf, and bbff. Only BbFf is the genotype that is heterozygous for both traits, and there are four offsprings with BbFf genotype.
Therefore the percentage of the offsprings that are heterozygous for both traits is 4/16 x 100 = 25%
See the punnett square for the details of the dibybrid cross
