Answer:
x = -2 + 2 i or x = -2 - 2 i
Step-by-step explanation:
Solve for x:
x^2 + 4 x + 8 = 0
Subtract 8 from both sides:
x^2 + 4 x = -8
Add 4 to both sides:
x^2 + 4 x + 4 = -4
Write the left hand side as a square:
(x + 2)^2 = -4
Take the square root of both sides:
x + 2 = 2 i or x + 2 = -2 i
Subtract 2 from both sides:
x = -2 + 2 i or x + 2 = -2 i
Subtract 2 from both sides:
Answer: x = -2 + 2 i or x = -2 - 2 i
Answer:
jvgdvfysvj fjrfhlgd ghcfh ghgdc
vurv gshgb gjjdvk jfdsuk0v
$1.50 for each box
Step-by-step explanation:
$18 divided by 12 boxes = $1.50 for each box
Well to factor a trinomial (Which is in the form ax^2 + bx + c) You would have to bring the A over to c so you can get x^2 alone. (If their isn't a gcf) You could also try to find what multiplys ac to add to b. but since that is not possible you would rewrite it x^2 -27x + 72 ( by multiplying the a to c) The you would rework it as normal (whatever two numbers multiply to 72 and add to -27. Which would be (x-3)(x-24). Then you would divide by the original A (x-3/18)(x-24/18). Then you would simplify that. (x-6)(x-4/3) and you would take any extra denominators and bring it to the front of the x. Making it (x-6)(3x-4)
