The perimeter of a rectangle is 40cm. If the length were doubled and the width halved, the perimeter would be increased by 16cm.
1 answer:
Answer:
The dimensions of the original rectangle are Length =12cm, Width=8cm
Step-by-step explanation
Let the length of the rectangle be x
Let the width of the rectangle be y
The perimeter of a rectangle is 40cm.
2(x+y)=40
Divide both sides by 2
x+y=20
If the length were doubled(2x) and the width halved(y/2), the perimeter would be increased by 16cm,i.e.(40+16)cm
Therefore:
Divide both sides by 2
From the first equation, x=20-y.
Substitute x=20-y into
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Answer:
3.) 0.894
Step-by-step explanation:
✔️First, find BD using Pythagorean Theorem:
BD² = BC² - DC²
BC = 17.89
DC = 16
Plug in the values
BD² = 17.89² - 16²
BD² = 64.0521
BD = √64.0521
BD = 8.0 (nearest tenth)
✔️Next, find AD using the right triangle altitude theorem:
BD = √(AD*DC)
Plug in the values into the equation
8 = √(AD*16)
Square both sides
8² = AD*16
64 = AD*16
Divide both sides by 16
4 = AD
AD = 4
✔️Find AB using Pythagorean Theorem:
AB = √(BD² + AD²)
AB = √(8² + 4²)
AB = √(64 + 16)
AB = √(80)
AB = 8.9 (nearest tenth)
✔️Find sin x using trigonometric ratio formula:
Reference angle = x
Opposite side = BD = 8
Hypotenuse = AB = 8.944
Thus:
(nearest thousandth)
Answer:
Step-by-step explanation:
The common ratio is 15/3 = 5.
The first term is 3.
So, the explicit rule is
