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Lapatulllka [165]

3 years ago

12

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP A

SAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

1 answer:

kvv77 [185]3 years ago

3 0

Answer:

I think that B is correct

Hope it helps

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Zepler [3.9K]

Answer:

9/28.26

Step-by-step explanation:

7 0

2 years ago

40 points please help

creativ13 [48]

IJKL is a rectangle, so opposite sides have the same length:

• IJ = KL ⇒ 6y - 6 = 2x + 20

• JK = IL ⇒ 3x + 21 = 6y

Substitute the second equation into the first and solve for x :

6y - 6 = 2x + 20

(3x + 21) - 6 = 2x + 20

3x + 15 = 2x + 20

x = 5

Solve for y :

3x + 21 = 6y

15 + 21 = 6y

36 = 6y

y = 6

4 0

2 years ago

A group of adults and students went on a class trip to Washington, DC. The number of male students was 1 more than 7 times the n

Helga [31]

In equation, let x be the number of male students
a be the number of adults
y be the number of female students.
x= 7a+1
a= x/7 -1
y= x/2 or (7a + 1)/ 2

a + b = 82, let b be the number of students.
a + (x + y) = 82
a + [7a+1 + (7a+1)/2] = 82
a + [{2(7a+1) + 7a+1} / 2] = 82
a + [(14a +2 + 7a +1) / 2] = 82
a + [(21a + 3) / 2] = 82
(2a+ 21a + 3) / 2 = 82
(23a + 3) / 2 = 82
23a + 3 = 164
23a = 164 -3
23a = 161
a = 7

x = 7(7) +1, 49+1 = 50 male students
y=x/2, 50/2, 25 female students

50(male students) + 25(female students) + 7 (adults) = 82

8 0

2 years ago

If two lines in space do not intersect the lines must be parallel

n200080 [17]

False. they could be skew

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4 0

2 years ago

Read 2 more answers

goldenfox [79]

Answer: $\frac{8}{17}$ or 8:17

Step-by-step explanation:

For any angle x (other than right angle) in a right triangle ,the trigonometric ratio of sin x is given by :-

$\sin x=\frac{\text{side opposite to x}}{\text{Hypotenuse}}$

Given: A right triangle with hypotenuse = 68 units

The side adjacent to S = 60

Let h be the side opposite to S, then using Pythagoras in the given right triangle, we get

$(68)^2=60^2+h^2\\\\\Rightarrow\ h^2=68^2-60^2\\\\\Rightarrow\ h^2=1024\\\\\Rightarrow\ h=\sqrt{1024}=32$

Thus, the side opposite to S = 32 units

Now, the trigonometric ratio for sin S is given by :-

$\sin S=\frac{\text{side opposite to S}}{\text{Hypotenuse}}\\\\\Rightarrow\sin S=\frac{32}{68}=\frac{8}{17}$

Hence, the trigonometric ratio for sin S = $\frac{8}{17}$ or 8:17

5 0

3 years ago