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shutvik [7]
3 years ago
7

If an object is dropped from a height of 85 feet, the function h(t)=-16t^2+85 gives the height of the object after t seconds. Ap

proximately, when will the object hit the ground?
a. 85.00 seconds
b. 69.00 seconds
c. 0.33 seconds
Mathematics
1 answer:
ziro4ka [17]3 years ago
6 0
C because all you need to do is compare the 2 variables and then add the variables and the multiply it and then divide it. Then your golden.
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The height of an overhand volleyball serve can be modeled as h=-16t^2+20t+6. After how many seconds is the ball 11 feet.
Andrew [12]

Answer:

0.9043secs and 0.3456secs

Step-by-step explanation:

Given the height of an overhand volleyball modeled as h=-16t^2+20t+6.

If the height is 11feet, then;

11 = -16t^2+20t+6.

-16t^2+20t+6 - 11 = 0

-16t^2+20t-5 = 0

Multiply thriugh by -1

16t^2-20t+5 = 0

Factorize

t = 20±√20²-4(16)(5)/2(16)

t = 20 ±√400-320/32

t = 20 ±√80/32

t = 20 ±4√5/32

t = 20±8.94/32

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t = 0.9043 and 0.3456

Hence the required time are 0.9043secs and 0.3456secs

8 0
3 years ago
Tom has 120 meters of fencing. He will use it to form three sides of a rectangular garden. The fourth side will be along a house
mezya [45]

Answer:

a) Function A(x) =  (60*x - 1/2*x²)

b)Side length     x = 60 m      the other side   y = 30 m

c) A (max)  = 1800 m²

Step-by-step explanation:

Area of rectangular garden with length  " x " and wide "y"

A = x*y        

Perimeter of rectangular area ( only three sides 2*y and 1*x)

P(r)  = 2*y + x

P(r) = 120 = 2*y + x

y = ( 120 - x ) /2

Area of the garden as function of x is

A(x) = [( 120 - x ) /2]*x          ⇒     A(x) = (60*x - 1/2*x²)

Taking derivatives on both sides of the equation:

A´(x) = 60 - x

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x = 60 m

Then

y = ( 120  -  x ) / 2                ⇒   y = (120 - 60 )/2

y = 30 m

A(max) = 30 * 60

A(max) = 1800 m²

8 0
4 years ago
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