Answer:
0.9043secs and 0.3456secs
Step-by-step explanation:
Given the height of an overhand volleyball modeled as h=-16t^2+20t+6.
If the height is 11feet, then;
11 = -16t^2+20t+6.
-16t^2+20t+6 - 11 = 0
-16t^2+20t-5 = 0
Multiply thriugh by -1
16t^2-20t+5 = 0
Factorize
t = 20±√20²-4(16)(5)/2(16)
t = 20 ±√400-320/32
t = 20 ±√80/32
t = 20 ±4√5/32
t = 20±8.94/32
t = 28.94/32 and 11.06/32
t = 0.9043 and 0.3456
Hence the required time are 0.9043secs and 0.3456secs
Answer:
a) Function A(x) = (60*x - 1/2*x²)
b)Side length x = 60 m the other side y = 30 m
c) A (max) = 1800 m²
Step-by-step explanation:
Area of rectangular garden with length " x " and wide "y"
A = x*y
Perimeter of rectangular area ( only three sides 2*y and 1*x)
P(r) = 2*y + x
P(r) = 120 = 2*y + x
y = ( 120 - x ) /2
Area of the garden as function of x is
A(x) = [( 120 - x ) /2]*x ⇒ A(x) = (60*x - 1/2*x²)
Taking derivatives on both sides of the equation:
A´(x) = 60 - x
A´(x) = 0 60 - x = 0
x = 60 m
Then
y = ( 120 - x ) / 2 ⇒ y = (120 - 60 )/2
y = 30 m
A(max) = 30 * 60
A(max) = 1800 m²
Multiply both sides by 39 to get 13=M