Read the question carefully: it costs 4 tokens to park in a garage for an hour.
We will apply the unitary method to solve this question
It costs 4 tokens to park in a garage for 1 hour
Find how many hours can park in a garage for 1 token
If it costs 4 token to park in a garage for 1 hour
Then it will cost 1 token to park in a garage for 1/4 hour
Step2:
With 20 token we can park in a garage for (1/4) * 20
= 5 hours
So, we can park for 5 hours with 20 tokens.
Another method
If we take twenty tokens and divide them into groups of four, we will find that we are left with five groups of tokens. Each group of tokens represents an hour of parking time. This will give us five groups, or five hours, total.
So, we can park for 5 hours with 20 tokens
I have summer school work too omg!!! it’s annoying
Answer:
2
Step-by-step explanation:
Given the question :
Serena wants to create snack bags for a trip she is going on. She has 6 granola bars and 10 pieces of dried fruit. If the snack bags should be identified without any food leftover, what is the greatest number of snack bags Serena can make?
Number of granolas = 6
Number of dried fruits = 10
Since the snackbag is to be designed in such a way that there should be no food leftover, the greatest number of snack bags Serena can make could be obtained by getting the highest common factor of (6 and 10)
____6____10
2___3____5
Here, the highest common factor of 6 and 10 is 2
Hence, the greatest number of snack bags she can make is 2.
To find the original price first put the % into decimal form.
58% is 0.58.
Then divide the discounted price ($116) by the % in decimal form:
116 / 0.58
Original price is $200.00
Answer:
Neema should get one box.
Step-by-step explanation:
Neema has 10 friends and each friend wants 2 cookies. 2x10 = 20 cookies, the exact amount that is included in a single box. So Neema only needs to get one box to satisfy everyone.