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Arlecino [84]
3 years ago
14

ILL GIVE BRAINLIEST A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equa

tion y = –0.02x2 + 2.3x + 6, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?
A. 57.50 m
B. 115.00 m
C. 117.55 m
D. 235.10 m
Mathematics
2 answers:
IceJOKER [234]3 years ago
7 0
The answer is C
hope this helps :)
Monica [59]3 years ago
4 0

Answer:

c)

Step-by-step explanation:

Simplifying

y = -0.02x2 + x + 2


Reorder the terms:

y = 2 + x + -0.02x2


Solving

y = 2 + x + -0.02x2


Solving for variable 'y'.


Move all terms containing y to the left, all other terms to the right.


Simplifying

y = 2 + x + -0.02x2

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faust18 [17]

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Please check the attached answer of picture for explanation.

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8 0
2 years ago
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What is the answer for 3x=1.2+1.2+1.2
Savatey [412]
The answer is 1.2 b/c you have to solve x by simplifying both sides of the equation and isolating the variable.
5 0
3 years ago
(-4,6); slope = -3/4​
yawa3891 [41]

Answer:

y-6=-3/4(x+4)

Step-by-step explanation:

y-y1=m(x-x1)

m=-3/4

y-6=-3/4(x-(-4))

y-6=-3/4(x+4)

6 0
3 years ago
18, 7<br> The LCM of 18 and 7 is
Korvikt [17]

Answer:

126

Step-by-step explanation:

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4 0
2 years ago
Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units. What would be the perimeters of the
Dmitriy789 [7]

Answer:

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

Step-by-step explanation:

Given - Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units.

To find -  What would be the perimeters of the other rectangles Orbet could make using only these 24 tiles? How do the areas of the rectangles compare?

Proof -

We know that

Are of Rectangle = Length × Breadth

And Perimeter of Rectangle = 2 (Length + Breadth )

Now,

Given that,

Orbet used 24 square tiles

And perimeter of the rectangle made = 20

So,

Possible Length of rectangle = 6

Possible breadth of Rectangle = 4

Or Vice-versa.

Total number of Rectangles possible = 4

Possibilities are -  1 × 24, 2 × 12, 3 × 8, 4 × 6

Case I :

Length of rectangle = 1

Breadth of rectangle = 24

∴ Perimeter of rectangle = 2(1 + 24) = 2(25) = 50 units

Area of rectangle = 1 × 24 = 24 unit²

Case II :

Length of rectangle = 2

Breadth of rectangle = 12

∴ Perimeter of rectangle = 2(2 + 12) = 2(14) = 28 units

Area of rectangle = 2 × 12 = 24 unit²

Case III :

Length of rectangle = 3

Breadth of rectangle = 8

∴ Perimeter of rectangle = 2(3 + 8) = 2(11) = 22 units

Area of rectangle = 3 × 8 = 24 unit²

Case IV :

Length of rectangle = 4

Breadth of rectangle = 6

∴ Perimeter of rectangle = 2(4 + 6) = 2(10) = 20 units

Area of rectangle = 4 × 6 = 24 unit²

∴ we get

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

5 0
3 years ago
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