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34kurt
1 year ago
6

Which values of m and b will create a system of equations with no solution? Select two options.

Mathematics
1 answer:
natima [27]1 year ago
3 0

Using linear function concepts, a system of equations with no solutions is created when:

m = -2, b \neq \frac{3}{2}

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

The intersection of two lines is the solution of a system of equations. If two lines have the <u>same slope and different intercepts</u>, they will never intercept, that is, the system will not have a solution.

The lines are given as follows:

  • y = mx + b.
  • y = -2x + 3/2.

Hence, for a system with no solution, we need that:

m = -2, b \neq \frac{3}{2}

More can be learned about linear function concepts at brainly.com/question/24808124

#SPJ1

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Sergeeva-Olga [200]

Answer:

11.9 mm

Step-by-step explanation:

We can find d by applying the cosine rules.

d²  = 21² + 27² - 2(21)(27) cos (25)

d²  = 441 + 729 - 1027.75

d²  = 142.25

d = √142.25

d = 11.9 mm (nearest tenth)

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Cant see

Step-by-step explanation:

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3 years ago
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RSB [31]

Answer:

Step-by-step explanation:

3x² - 3x + 7 = 0

a = 3 ; b = -3 and c = 7

D = b² - 4ac = (-3)² - 4*3*7

D = 9 - 84 = - 75

D = 75i²

√D = √75i² = \sqrt{5*5*3 * i * i}= 5i\sqrt{3}

x = \dfrac{-b+\sqrt{D}}{2a}  \ ; \  x=\dfrac{-b-\sqrt{D}}{2a}\\\\ \\x=\dfrac{3+5i\sqrt{3}}{6} ; \ ; x = \dfrac{3-5i\sqrt{3}}{6}\\\\\\x =\dfrac{3}{6}+\dfrac{5i\sqrt{3}}{6} ; \ ; x=\dfrac{3}{6}-\dfrac{5i\sqrt{3}}{6}\\\\\\Solution:\\\\x=\dfrac{1}{2}+\dfrac{5\sqrt{3}}{6}i ; \ ; x=\dfrac{1}{2}-\dfrac{5\sqrt{3}}{6}i

5 0
2 years ago
What is the area of a triangle for one of the legs being 3in and the hypotenuse being 9in
elena55 [62]

The area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches is 12.727 square inches

<em><u>Solution:</u></em>

Given that to find area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches

From given information,

Let "c" = hypotenuse = 9 inches

Let "a" = length of one of the leg of triangle = 3 inches

To find: area of triangle

<u><em>The area of triangle when hypotenuse and length of one side of triangle is given:</em></u>

A = \frac{1}{2} a \sqrt{c^2 - a^2}

Where, "c" is the length of hypotenuse

"a" is the length of one side of triangle

Substituting the given values we get,

A = \frac{1}{2} \times 3 \times \sqrt{9^2 - 3^2}

A =\frac{1}{2} \times 3 \times \sqrt{81-9}\\\\A =\frac{1}{2} \times 3 \times \sqrt{72}\\\\A =\frac{1}{2} \times 3 \times 8.48528\\\\A = \frac{1}{2} \times 25.45584\\\\A = 12.727

Thus area of triangle is 12.727 square inches

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3 years ago
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Artyom0805 [142]

Answer:

3 hot dogs and 5 drinks

Step-by-step explanation:

(3x2)+(1x5)

=(6)+(5)

=11

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3 years ago
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