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Viktor [21]
3 years ago
10

If Sam has 5 blue shirts and 7 red shirt, what is Sam's ratio of blue shirts to red shirts?

Mathematics
1 answer:
saw5 [17]3 years ago
5 0

Answer: 0.71428 or 5:7 or 5/7

Step-by-step explanation: just divide on a calculator

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May I please receive help?
goblinko [34]

Answer:

4.8 feet

Step-by-step explanation:

a² + b² = c²

a² + 11² = 12²

a² + 121 = 144

a² = 23

a = \sqrt{23}

a, or the height of the kite ≈ 4.8

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

6 0
2 years ago
Read 2 more answers
Which is bigger 1/12 or 12%?
Archy [21]
12% would be bigger because it is a whole number other then the fraction.
7 0
3 years ago
Read 2 more answers
Kesha threw her baton up in the air from the marching band platform during practice. The equation h(t) = −16t² + 54t + 40 gives
lapo4ka [179]

Answer:

a) 40 feet

b) 54 ft/min

c) 4 mins

Step-by-step explanation:

Solution:-

- Kesha models the height ( h ) of the baton from the ground level but thrown from a platform of height hi.

- The function h ( t ) is modeled to follow a quadratic - parabolic path mathematically expressed as:

                           h ( t ) = −16t² + 54t + 40

Which gives the height of the baton from ground at time t mins.

- The initial point is of the height of the platform which is at a height of ( hi ) from the ground level.

- So the initial condition is expressed by time = 0 mins, the height of the baton h ( t ) would be:

                         h ( 0 ) = hi = -16*(0)^2 + 54*0 + 40

                         h ( 0 ) = hi = 0 + 0 + 40 = 40 feet

Answer: The height of the platform hi is 40 feet.

- The speed ( v ) during the parabolic path of the baton also varies with time t.

- The function of speed ( v ) with respect to time ( t ) can be determined by taking the derivative of displacement of baton from ground with respect to time t mins.

                        v ( t ) = dh / dt

                        v ( t )= d ( −16t² + 54t + 40 ) / dt

                        v ( t )= -2*(16)*t + 54

                        v ( t )= -32t + 54

- The velocity with which Kesha threw the baton is represented by tim t = 0 mins.

Hence,

                        v ( 0 ) = vi = -32*( 0 ) + 54

                        v ( 0 ) = vi = 54 ft / min

Answer: Kesha threw te baton with an initial speed of vo = 54 ft/min

- The baton reaches is maximum height h_max and comes down when all the kinetic energy is converted to potential energy. The baton starts to come down and cross the platform height hi = 40 feet and hits the ground.

- The height of the ball at ground is zero. Hence,

                     h ( t ) = 0

                     0 = −16t² + 54t + 40

                     0 = -8t^2 + 27t + 20

- Use the quadratic formula to solve the quadratic equation:

                     

                    t = \frac{27+/-\sqrt{27^2 - 4*8*(-20)} }{2*8}\\\\t = \frac{27+/-\sqrt{1369} }{16}\\\\t = \frac{27+/-37 }{16}\\\\t =  \frac{27 + 37}{16} \\\\t = 4

Answer: The time taken for the baton to hit the ground is t = 4 mins

3 0
3 years ago
If y2 = x3 + 2, which statement is true? The equation is a function at all values of x. The equation is not a function. The equa
tatyana61 [14]

Answer:

The equation is not a function.

Step-by-step explanation:

We are given that

y^2=x^3+2

y=\pm\sqrt{x^3+2}

Function: It is mapping between the values of two sets A and B.

Each element of A has unique value in set B.

By definition of  function

In given function

y has no unique value for each value of x.

Substitute x=0

y=\pm \sqrt{0+2}=\pm \sqrt 2

Hence, it is not a function.

6 0
3 years ago
Apply root test to the series.
Angelina_Jolie [31]
\displaystyle\lim_{n\to\infty}\sqrt[n]{\left|\left(\frac{5n+15}{2n-1}\right)^n\right|}=\lim_{n\to\infty}\frac{5n+15}{2n-1}=\dfrac52

Since this limit exceeds 1, the series diverges.
8 0
3 years ago
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