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vichka [17]

3 years ago

by 19,594" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Vaselesa [24]3 years ago

3 0

0.02521179 jdjdjdduhdbdjdhdhj

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The cross-sectional areas of a triangular prism and a right cylinder are congruent. The triangular prism has a height of 5 units

Yanka [14]

Answer:

Step-by-step explanation:

The volume of the prism is not equal to the volume of the cylinder.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the cross sectional areas of a triangular prism and a right cylinder.

Volume of cylinder = cross sectional area * height = 3 * x = 3x

Volume of triangular prism = cross sectional area * height = 5 * x = 5x

The volume of the prism is not equal to the volume of the cylinder.

Find out more on equation at: brainly.com/question/2972832

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7 0

2 years ago

(b) XYZ limited had sales of Sh.700,00 in its first year of operation. If the sales increased by Sh.250,000 thereafter, find the

ki77a [65]

Answer:

XYZ IS THE ANSWER ok now wat

Step-by-step explanation:

4 0

3 years ago

What's 5.17÷186 ? The directions for the assignment that I was forced to do is above.

My name is Ann [436]

0.0277956989 I really hope this helps you out!

7 0

3 years ago

Which situation can be modeled by the equation y=3x+25

Gnesinka [82]

For this case we have the following situation:

The monthly cost of a gym in the city is $ 3. The initial registration is $ 25. Write a mathematical expression that models the problem.

So we have to define variables:

x: number of months

y: total cost

The mathematical expression that models the problem is:

$y = 3x + 25$

7 0

3 years ago

I need help on these question ASAP!!!! This is Urgent

GarryVolchara [31]

Part 1: The equation of the line is $y=2x+1$

Part 2: The equation of the line in slope intercept form is $y=-3x-1$

Explanation:

Part 1: It is given that the point A is $(1,3)$ and the line B is $y=2 x-2$

To determine the line passing through the point A and parallel to line B, let us first determine the slope and y-intercept.

From the equation of line B, the slope is $m=2$

Substituting the point $(1,3)$ and $m=2$ in slope intercept form $y=mx+b$ , we have,

$3=2(1)+b$

$3=2+b$

$1=b$

Thus, the y-intercept is $b=1$

Let us substitute the values $m=2$ and $b=1$ in the slope intercept form $y=mx+b$ , we get,

$y=2x+1$

Thus, the equation of the line passing though point A and parallel to line B is $y=2x+1$

Part 2: The given two coordinates are $(-1,2)$ and $(1,-4)$

To determine the equation of line in slope intercept form, first we shall find the slope and y-intercept.

From the graph, we can see that the line touches the y-axis at -1.

Hence, the y-intercept is $b=-1$

The formula for slope is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting the coordinates $(-1,2)$ and $(1,-4)$ , we have,

$m=\frac{-4-2}{1+1} =\frac{-6}{2} =-3$

Thus, the slope is $m=-3$

Substituting the values $b=-1$ and $m=-3$ in the slope intercept formula $y=mx+b$ , we get,

$y=-3x-1$

Thus, the equation of the line in slope intercept form is $y=-3x-1$

4 0

3 years ago