You would basically work backwards and do inverse operations
12
24*
__
288
288/24= 12
Answer:
Rounding to nearest hundredths gives us r=0.06.
So r is about 6%.
Step-by-step explanation:
So we are given:
where
.
Divide both sides by 1600:
Simplify:
Take the 6th root of both sides:
![\sqrt[6]{\frac{23}{16}}=1+r](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B%5Cfrac%7B23%7D%7B16%7D%7D%3D1%2Br)
Subtract 1 on both sides:
![\sqrt[6]{\frac{23}{16}}-1=r](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B%5Cfrac%7B23%7D%7B16%7D%7D-1%3Dr)
So the exact solution is ![r=\sqrt[6]{\frac{23}{16}}-1](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B6%5D%7B%5Cfrac%7B23%7D%7B16%7D%7D-1)
Most likely we are asked to round to a certain place value.
I'm going to put my value for r into my calculator.
r=0.062350864
Rounding to nearest hundredths gives us r=0.06.
Don’t invest too much into it
Answer:
Domain and range » Tips for entering queries. Enter your queries using plain English. To avoid ambiguous queries, make sure to use parentheses where necessary. Here are some examples illustrating how to ask for the domain and range. domain of log(x) (x^2+1)/(x^2-1) domain; find the domain of 1/(e^(1/x)-1) function domain: square root of cos(x)
Step-by-step explanation:
and when they got there they all got teleported back in time 66, 000, 000 years ago to the dinosaurs
