Answer:
x = 18, y = 45
Step-by-step explanation:
4x - 7 + a = 180 (linear pair)
But, a = 6x + 7 (alternate interior angles)
=> 4x - 7 + 6x + 7 = 180
=> 10x = 180
=> x = 18
Now, 3y - 20 = 6x + 7 (vertically opposite angles)
=> 3y - 20 = 6(18) + 7
=> 3y = 108 + 7 + 20
=> 3y = 135
=> y = 45
Hope it helps :)
Please mark my answer as the brainliest
10 n = C
Finding the total would simply be multiplying the cost of the tickets by number of students.
Answer:
Our answer is 0.8172
Step-by-step explanation:
P(doubles on a single roll of pair of dice) =(6/36) =1/6
therefore P(in 3 rolls of pair of dice at least one doubles)=1-P(none of roll shows a double)
=1-(1-1/6)3 =91/216
for 12 players this follows binomial distribution with parameter n=12 and p=91/216
probability that at least 4 of the players will get “doubles” at least once =P(X>=4)
=1-(P(X<=3)
=1-((₁₂ C0)×(91/216)⁰(125/216)¹²+(₁₂ C1)×(91/216)¹(125/216)¹¹+(₁₂ C2)×(91/216)²(125/216)¹⁰+(₁₂ C3)×(91/216)³(125/216)⁹)
=1-0.1828
=0.8172
<span>46, 37, 16, 24, 47, 23, 19, 31, 25
put in order</span>
16, 19, 23, 24, 25, 31,37, 46, 47
mean = 25
LOWER QUARTILE = (16+ 19+ 23+ 24) / 4 = 20.5
answer
Lower IQR = 20.5
we are given with
The polynomial x squared plus 2x minus 24
Hence the required combination is 6x and -4x
