The polynomial is (mx^3+3)(2x²+5x+2)-(8x^5 +20x^4)
if it is reduced to 8x^3+6x²+15x+6, so we can find the value of m
(mx^3+3)(2x²+5x+2)-(8x^5+20x^4) = <span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3+6x²+15x+6-8x^5-20x^4=<span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3=8x^3+6x²+15x+6-6x²-15x-6+ <span>8x^5+20x^4
</span>= 8x^5+20x^4+<span>8x^3= 4(2x^5+5x^4+2x^3)
finally
</span>m(2x^5+5x^4+2x^3)=<span>4(2x^5+5x^4+2x^3), and after simplification
</span>
C: m=4
<span>4. When the expression is factored x²-3x-18 completely,
</span>
one of its factor is x-6
<span>x²-3x-18=0
</span>D= 9-4(-18)= 81, sqrtD=9 x=3-9/2= -6/2= -3, and x=3+9 / 2= 6
so <span>x²-3x-18= (x-6)(x+6)
</span>
1/2 + 3/x = 3/4
multiply everything by x
1/2x + 3 = 3/4x...subtract 1/2x from both sides
3 = 3/4x - 1/2x
3 = 3/4x - 2/4x
3 = 1/4x...multiply both sides by 4
4 * 3 = x
12 = x
Answer:
No.
Step-by-step explanation:
9 Does not go into 47 or 23
Answer:
x= -4, -3, 3
Step-by-step explanation:
You must factor this equation.
Once you factor, you get (x+4)(x-3)(x+3)
Set this equal to 0 and solve.
You get -4,-3, and 3.
Answer:
A is the answer.
Step-by-step explanation:
C=2πr
/2π /2π
C/2π=r
