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Alenkinab [10]
3 years ago
12

A system of equations can be solved by elimination in the table below. Does the system of equations on line 4 have the same solu

tion set as the system of equations on line 1? why or why not?

Mathematics
1 answer:
devlian [24]3 years ago
8 0

Answer:

Full question attached below.

Yes, the system of equations on line 4 has the same solution set as the system of equations on line 1

Step-by-step explanation:

There is no difference between the systems of line 1 and 4

1st system

5x + 3y = 14

4x - 2y = -2

4th system

10x + 6y = 28

12x - 6y = -6

In the fourth system, we factor number 2 from the first line, and number 3 from the second line

4th system

2[5x + 3y] = 2[14]

3[4x - 2y] = 3[-2]

If we simplify,

4th system

[5x + 3y] = [14]

[4x - 2y] = [-2]

We get the same system as the 1st

Therefore, the solution is the same.

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3 years ago
Jerry says I've got my money in a great account that compounds interest monthly. The equation y=388 (1.008) represents how much
zheka24 [161]

Answer:

(a)His monthly Interest Rate=0.8%

(b)Annual Interest Rate = 9.6%

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Step-by-step explanation:

For a Principal P invested at a yearly rate r, compounded m times in t years

Amount at Compound Interest= P(1+\frac{r}{m})^{mt}

Comparing with Jerry's equation y=388 (1.008)

(a)His monthly Interest Rate= 0.008=0.8%

(b)Annual Interest Rate= Monthly Interest Rate X 12 =0.8 X 12 = 9.6%

(c)If I invest $500 at the same rate of return,

Total Money after m months

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7 0
3 years ago
Please help me on this math please
makkiz [27]
1=60
2=120
3=120
4=180
5=240
6=300
and you have arrived bu now. :)
Good luck with your lessons, hope I helped. :D
8 0
3 years ago
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