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frosja888 [35]
3 years ago
13

Triangle DEF has an angle D measuring 25 degrees and an angle E

Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

The angle F of the triangle DEF measures 105 degrees.

Step-by-step explanation:

Given that triangle DEF has an angle D measuring 25 degrees and an angle E measuring 50 degrees, to determine what is the measure of angle F in degrees, knowing that the sum of the internal angles of every triangle gives a total of 180 degrees, we must perform the following calculation:

180 - 50 - 25 = F

130 - 25 = F

105 = F

Therefore, the angle F of the triangle DEF measures 105 degrees.

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Find the slope of the line that contains the points (2, 2) and (-7,-4).
yKpoI14uk [10]

Answer:

6, 9

Step-by-step explanation:

y1-y2 over x1-x2

slope formula ^^

3 0
3 years ago
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5.) Evaluate the function. f(x)=8x+9 for f(5). Show your work and write your
irina1246 [14]

Answer:

49

Step-by-step explanation:

f(5)=8×5+9=40+9=49

7 0
3 years ago
The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0
3 years ago
The cost of 3 ibs of turkey is $9.81. What is the cost per pound for the turkey?
butalik [34]
3 = $9.81

1 = $?

To find this you have to do 9.81/3.

Hope this helps and have a nice day!!
3 0
3 years ago
8. Graph the following linear equations.<br> a. 3x+5y=15
kenny6666 [7]

Answer:

slope: -3/5

y-intercept (0,3)

x    -      y

0          3

5          0

Step-by-step explanation:

I just did it

4 0
2 years ago
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