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Sidana [21]
3 years ago
12

The sum of three consecutive integers is greater than 66. What is the smallest possible product of the largest and smallest of t

hese integers?
Please help me on this
Mathematics
1 answer:
AysviL [449]3 years ago
4 0

Answer:

528

Step-by-step explanation:

So naturally at first sight for this question we would think -->

Oh 3 consecutive integers = 66 --> 66/3 = 22 (n-1), (n+1) so --> 21, 22, and 23.

But no. At second look it is the sum of 3 consecutive integers is greater than 66. So we find the next possible pair since it says smallest possible product.

We get the set (22, 23, 24). => Multiply the least and greatest integers together respectively 22 and 24 which amounts to => 528

And thus, we have out answer of 528

Hope this helps!

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