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Sidana [21]
3 years ago
12

The sum of three consecutive integers is greater than 66. What is the smallest possible product of the largest and smallest of t

hese integers?
Please help me on this
Mathematics
1 answer:
AysviL [449]3 years ago
4 0

Answer:

528

Step-by-step explanation:

So naturally at first sight for this question we would think -->

Oh 3 consecutive integers = 66 --> 66/3 = 22 (n-1), (n+1) so --> 21, 22, and 23.

But no. At second look it is the sum of 3 consecutive integers is greater than 66. So we find the next possible pair since it says smallest possible product.

We get the set (22, 23, 24). => Multiply the least and greatest integers together respectively 22 and 24 which amounts to => 528

And thus, we have out answer of 528

Hope this helps!

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Sonja [21]

Answer:

see explanation

Step-by-step explanation:

(a)

Given

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Its the last one

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Breakfast Bar’s scrambled egg recipe uses 8 eggs to feed 5 people. How many eggs are they going to need to serve 100 people on S
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40 units2˛

   Looking at the figure, the rectangle has the vertexes (2,1), (3,-3), (-5,-5) and (-6,-1). The parallelogram has the vertexes (2,7), (3,3), (3,-3), and (2,1).

The area of a parallelogram is base times height. We have 2 vertical lines at x=2 and x=3, so the height is 1. And the length of the line from (3,3) to (3,-3) is 6, so the base is 6. Therefore the area of the parallelogram is 1*6 = 6.

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 L = sqrt((2 - -6)^2 + (1 - -1)^2)

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  W = sqrt((2-3)^2 + (1- -3)^2)

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