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Sidana [21]
3 years ago
12

The sum of three consecutive integers is greater than 66. What is the smallest possible product of the largest and smallest of t

hese integers?
Please help me on this
Mathematics
1 answer:
AysviL [449]3 years ago
4 0

Answer:

528

Step-by-step explanation:

So naturally at first sight for this question we would think -->

Oh 3 consecutive integers = 66 --> 66/3 = 22 (n-1), (n+1) so --> 21, 22, and 23.

But no. At second look it is the sum of 3 consecutive integers is greater than 66. So we find the next possible pair since it says smallest possible product.

We get the set (22, 23, 24). => Multiply the least and greatest integers together respectively 22 and 24 which amounts to => 528

And thus, we have out answer of 528

Hope this helps!

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What is the following product? square root 30 times square root 10
egoroff_w [7]

Answer:

D. 10 square root 3 is your answer

Step-by-step explanation:

Here is what you do.

<em>square root 30 = 3 x 2 x 5 </em>

<em>square root 10 = 2 x 5</em>

Add them together.

<em>3 x 2 x 2 x 5 x 5 </em>

<em>3 x 4 x 25.</em>

4 and 25 can come out of the square root.

<em>2 x 5 = 10</em>

10 square root 3 is your answer.

4 0
2 years ago
Which expression is equivalent to 6x^2 + 13x + 5?
hodyreva [135]

The signs of the x-term and the constant term are both positive, so the signs of the constants in the binomial factors must be the same and must both be positive. The only offering that meets that requirement is

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If you multiply that out, you get 6x² + 10x + 3x + 5 = 6x² +13x +5, as required.

The sign of the constant term is the product of the signs of the constants in the binomial factors: (+1)·(+5). We want a positive sign for the constant, so both binomial factor constants must have the same sign.

When the signs of the binomial factor constants are the same, the x-term constant will match them. Thus, for a positive x-term constant, both binomial factor constants must be positive.

3 0
2 years ago
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Answer:

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Step-by-step explanation:

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