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salantis [7]
3 years ago
8

Which of the equations below could be the equatiom of this parabola

Mathematics
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

D

Step-by-step explanation:

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Hello hope your day is well i really need help with this expand question 4(a+5)-2(a-5)
BARSIC [14]

Answer:

2a + 30

Step-by-step explanation:

break it down so it is 4(a+5)

then work out -2(a-5)

so 4 x a then 4 x 5 which gives 4a + 20

then -2 x a then -2 x -5 which gives -2a + 10

then when you have 4a + 20 -2a + 10

do 4a - 2a which is 2a

do 20 + 10 which is 30

so the answer comes to 2a + 30

if anything doesnt seem right just comment and i will correct

hope this helps :)

6 0
3 years ago
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Jenny makes food for her hummingbird feeders. The food is made up of 1 part sugar and 4 parts water. She uses 3434 cup of sugar
kati45 [8]
13736 cups. I may be wrong.
6 0
3 years ago
Ik it seems easy but can someone help
White raven [17]
What are you suppose to find i feel like it doesn't really say
5 0
3 years ago
Represent the following sentence as an algebraic expression, where "a number" is the letter x.
agasfer [191]

Answer:

x-1

Step-by-step explanation:

it is x-1 because 1 is subtracted from a number and the number is x. when it says subtracted from you flip the equation and put the first number last and put a minus sign.

7 0
3 years ago
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An article written for a magazine claims that 78% of the magazine's subscribers report eating healthily the previous day. Suppos
Schach [20]

Answer:

89.44% probability that less than 80% of the sample would report eating healthily the previous day

Step-by-step explanation:

We use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.78, n = 675

So

\mu = E(X) = np = 675*0.78 = 526.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{675*0.78*0.22} = 10.76

What is the approximate probability that less than 80% of the sample would report eating healthily the previous day?

This is the pvalue of Z when X = 0.8*675 = 540. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{540 - 526.5}{10.76}

Z = 1.25

Z = 1.25 has a pvalue of 0.8944

89.44% probability that less than 80% of the sample would report eating healthily the previous day

8 0
3 years ago
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