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3 years ago

What is the first “given” on number 7?

Mathematics

2 answers:

stich3 [128]3 years ago

4 0

I assume that the IG and IJ are equal is the given.

I am Lyosha [343]3 years ago

4 0

Answer:

i think that's an error. if it was a given, they would have given it like the second given statement. i would leave it blank if i were you.

Step-by-step explanation:

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When I write my expression in rational exponent form, what is the fraction that goes with the base of 10?

blsea [12.9K]

Answer: Choice A

$\sqrt[4]{3^3}$

The fourth root of 3^3

=============================================

Explanation:

The exponent of 1/4 means "fourth root", so,

$3^{1/4} = \sqrt[4]{3}$

The outer exponent 3 can be moved inward like this

$\left(3^{1/4}\right)^3 = 3^{1/4*3} = 3^{3/4}$

Then we can use the rule

$x^{m/n} = \sqrt[n]{x^m}$

This means

$3^{3/4} = \sqrt[4]{3^3}$

6 0

3 years ago

If a = 4 - √15, find a^4 +1\a^4

Luden [163]

Answer:

$(\frac{-3+\sqrt{15} }{4-\sqrt{15} })^{2} -4\\$

Step-by-step explanation:

$a=4-\sqrt{15}$

$a^{4} +\frac{1}{a^{4} }\\=a^{2^{2} } +\frac{1}{a^{2^{2} } }\\\\=(x^{2} +\frac{1}{a^{2} } )^{2} -2a^{2} \frac{1}{a^{2} } \\=(a +\frac{1}{a } )^{2} -2a \frac{1}{a}-2\\=(4-\sqrt{15} +\frac{1}{4-\sqrt{15} }) ^{2} -4\\\=(\frac{16-15-4+\sqrt{15} }{4-\sqrt{15} })^{2} -4\\=(\frac{-3+\sqrt{15} }{4-\sqrt{15} })^{2} -4\\$

7 0

3 years ago

Need help due in 10 mins

kap26 [50]

Answer:

X = 3

Step-by-step explanation:

3x + 4x - 12 = - 10x + 30 + 9

7x - 12 = - 10x + 39

7x + 10x = 12 + 39

17x = 51

x = 3

4 0

2 years ago

Help quickly please thank you

kondaur [170]

Answer: 1024

Step-by-step explanation:

30+2 * 30+2

32 * 32

1024

6 0

3 years ago

Read 2 more answers

Help me plz thank you

Travka [436]

Answer: 2nd one

Hard to explain

Pls give brainliest.

3 0

2 years ago