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Sonja [21]
3 years ago
10

Michael and Angelo live in a small town in Italy. They work as artists. Michael is the more productive artist; he can produce 12

small sculptures each day, but only 10 paintings. Angelo can produce 5 sculptures, but only 3 paintings. Sclupture/day paintings/dayMichael 10 5Angelo 6 2What is the opportunity cost of painting for each artist?
Mathematics
1 answer:
eduard3 years ago
5 0

Answer:

Cost of opportunity is 12 small sculptures for Michael and 5 sculptures for Angelo.

Step-by-step explanation:

The cost of opportunity is the alternative that you sacrifice when you choose an option.  

It represents the benefits that you miss out on when choosing one alternative over another.  

In this case,  the cost of opportunity<u> of painting</u> for each artist is the quantity of sculptures that they can make in the same time.

So, cost of opportunity is 12 small sculptures for Michael and 5 sculptures for Angelo.

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The overhead reach distances of adult females are normally distributed with a mean of 205.5 and a standard deviation of 8.6 . a.
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Answer:

a) 0.073044

b) 0.75033

c) The normal distribution can be used in part (b), even though the sample size does not exceed 30 because initial population size is been distributed normally , therefore, the mean of the samples will be normally distributed regardless of their size(meaning whether the sample size is less than or equal to or exceeds 30, the sample means the mean of the samples will be normally distributed regardless of their size).

Step-by-step explanation:

The overhead reach distances of adult females are normally distributed with a mean of 205.5 and a standard deviation of 8.6 .

a. Find the probability that an individual distance is greater than 218.00 cm.

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = 218

μ is the population mean = 205.5

σ is the population standard deviation = 8.6

For x > 218

z = 218 - 205.5/8.6

z = 1.45349

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P(x>218) = 1 - P(x<218) = 0.073044

b. Find the probability that the mean for 15 randomly selected distances is greater than 204.00

When = random number of samples is given, we solve using this z score formula

z = (x-μ)/σ/√n

where

x is the raw score = 204

μ is the population mean = 205.5

σ is the population standard deviation = 8.6

n = 15

For x > 204

Hence

z = 204 - 205.5/8.6/√15

z = -0.67552

Probability value from Z-Table:

P(x<204) = 0.24967

P(x>204) = 1 - P(x<204) = 0.75033

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The normal distribution can be used in part (b), even though the sample size does not exceed 30 because initial population size is been distributed normally , therefore, the mean of the samples will be normally distributed regardless of their size(meaning whether the sample size is less than or equal to or exceeds 30, the sample means the mean of the samples will be normally distributed regardless of their size).

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3 years ago
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Using delta method:

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5 to 6 = +1

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The line intercepts the y-axis at (0, 4)

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2 years ago
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wait
oooooh, she has a supply of blood other than her own, nvm, I should read better


1 decileter is 1/10 of a liter
so 3/10 of a liter per glass

6 of those 2 liter bottles
so total is 6*2=12 liters
so
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times both sides by 10/3
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