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3 years ago

F(1) = 4, f(n) = f(n − 1) + 11

Mathematics

1 answer:

zvonat [6]3 years ago

4 0

Answer:

Step-by-step explanation:

You don't specify what you're supposed to do, so I'll make an educated guess.

Given the sequence f(1) = 4, f(n) = f(n − 1) + 11, find the first 5 terms:

f(1) = 4

f(2) = f(2 - 1) + 11 = f(1) + 11 = 4 + 11 = 15

f(3) = f(2) + 11 = 15 + 11 = 26

f(4) = f(3) + 11 = 26 + 11 = 37

f(5) = 37 + 11 = 48

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Geometry Help Please!!

Reil [10]

Answer:

b=130°

Step-by-step explanation:

b=180°-50°=130°

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3 years ago

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How many inches are in a meter.!!!!!!!!!!!!!!!!!!!???????????<br> I will mark brainliest.

7nadin3 [17]

Answer:

39.3701

Step-by-step explanation:

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Rewrite the equation of the parabola in vertex form. y= x2 + 8x - 21

sergey [27]

Answer:

$y=(x+4)^{2}-37$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$y=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

if a> 0 then the parabola open upward (vertex is a minimum)

if a< 0 then the parabola open downward (vertex is a maximum)

In this problem we have

$y=x^{2}+8x-21$

Convert to vertex form

Complete the square

$y+21=x^{2}+8x$

$y+21+16=(x^{2}+8x+16)$

$y+37=(x^{2}+8x+16)$

$y+37=(x+4)^{2}$

$y=(x+4)^{2}-37$ --------> equation in vertex form

The vertex is the point $(-4,-37)$

the parabola open upward (vertex is a minimum)

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3 years ago

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The area of an equilateral triangle is given by A =3^1/2/4s^2. Find the length of the side s of an equilateral triangle with an

yan [13]

Answer:

The length of the side of an equilateral traingle $s=2\sqrt{2}$ inches

Step-by-step explanation:

Given that the area of an equilateral triangle is given by

$A=3^\frac{1}{2}s^2$

It can be written as

$a=\frac{\sqrt{3}}{4} s^2$ Square inches (1)

To find the length of the side s os an equilateral triangle

Given that area of an equilateral triangle is $12^\frac{1}{2}$ square inches

It can be written as

$A=12^\frac{1}{2}$

$A=\sqrt{12}$ square inches

It can be written as

$A=12^\frac{1}{2}$

$A=\sqrt{12}$ square inches (2)

Now comparing equations (1) and (2) we get

$\frac{\sqrt{3}}{4}s^2=\sqrt{12}$

$\frac{\sqrt{3}}{4}s^2=\sqrt{4\times 3}$

Dividing by $\frac{\sqrt{3}}{4}$ on both sides we get

$\frac{\frac{\sqrt{3}}{4}s^2}{\frac{\sqrt{3}}{4}}=\frac{2\sqrt{3}}{\frac{\sqrt{3}}{4}}$

$\frac{\sqrt{3}}{4}s^2\times\frac{4}{\sqrt{3}}=2\sqrt{3}\times\frac{4}{\sqrt{3}}$

$s^2=8$

$s=\sqrt{8}$

Therefore $s=2\sqrt{2}$ inches

Therefore the length of the side of an equilateral traingle $s=2\sqrt{2}$ inches

3 0

3 years ago

Consider the sets below.

Pepsi [2]

Answer:

B ⊂ A

Step-by-step explanation:

We know that:

A {x|x is a polygon}

So set A is the set of all polygons.

B {x|x is a triangle}

Set B is the set of all triangles.

First, a polygon is a plane geometrical figure made of a finite sequence of straight segments.

For example, a triangle is a polygon, a rectangle is a polygon, etc.

Then, all triangles are polygons, but not all polygons are triangles.

So we can conclude that the whole set B is included in the set A.

Then the correct notation would be:

B ⊂ A

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3 years ago

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