Answer:
(a)2(89x+84)
(b)
Step-by-step explanation:
The dimensions of the larger rectangular field are:
- Length=5x + 12; Width
= 9x + 14.
The dimensions of the smaller rectangular soccer field are:
(a)Area of the part of the field that is outside the soccer field
=Area of the larger rectangular field - Area of the Soccer Field
=(5x+12)(9x+14)-5x(9x)
=(5x)(9x)+70x+108x+168-5x(9x)
=178x+168
=2(89x+84)
(b)Radius of the Semicircular Fountain =2x
From Part (a),
Area of the larger rectangular field - Area of the Soccer Field=178x+168
Area of the Semicircular Fountain =
Area of the Field that does not include the soccer field or the fountain.
=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

Answer:
A≈351.86 or rounded to the nearest tenth, 351.9.
7/12 - 3/12 = 1/3
Simplify each fraction if possible.
Same denominator? YES!
7 - 3 = 4
Since they have the same denominator, you just subtract the numerators.
Then simplify 4/12
4/4= 1 12/4= 3
Answer: 1/3
Hope that helps!
Y equals 5 over 7x minus 5
The vertex to the equation is, (4,2)