Answer/Step-by-step explanation:
[1] x+9+1+3x
Add the numbers
x + 10 +3x
Combine like terms
4x+10
Common factor
2(2x+5)
<u>Solution = </u><u>2(2x+5)</u>
<u>.............................................................................................................................................</u>
[2] 5a+6c+2a+3c
Combine like terms
7a+6c+3c
Combine like terms
7a+9c
<u>Solution</u><u> = 7a + 9c</u>
<u>...............................................................................................................................................</u>
[3] 5n+6m+3n
Combine like terms
8n + 6m
Rearrange terms
6m + 8n
<u>Solution </u><u>= 6m+8n</u>
<u>.............................................................................................................................................</u>
[RevyBreeze]
Let's say you want to compute the probability
where
converges in distribution to
, and
follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing
such that its mean and variance are the same as those for
.
Example: If
is binomially distributed with
and
, then
has mean
and variance
. So you can approximate a probability in terms of
with a probability in terms of
:
where
follows the standard normal distribution.
Answer:
20
Step-by-step explanation:
16=1 2/10R + -8
16+8= 12/10R
24=12/10R
R=20
Again, what is the shape?
J. 5a + 8 I think
I just added everything together