Question

Which equation has a graph that is parallel to the graph of 15x - 16y = 1? Select one:

Answer 1

We know that
if two lines are parallel
then
the slopes are the same

we have 
15x - 16y = 1
solve for y
16y=15x-1
y=(15/16)x-(1/16)
m=15/16

case A) 
16x - 15y = 1 
15y=16x-1
y=(16/15)x-(1/15)
m=16/15------> is not equal to 15/16

case B)
15x + 16y = 1 
16y=1-15x
y=(1/16)-(15/16)x
m=-15/16-------> is not equal to 15/16

case C) 
y = (15/16) x - 7
m=15/16---------> is equal to 15/16
so
this equation is parallel to 15x - 16y = 1

case D) 
y = (16/15) x - 7
m=16/15-------> is not equal to 15/16

therefore

the answer is the option
C y = (15/16) x - 7