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mars1129 [50]
2 years ago
11

The parking garage has 9 rows with 10 parking space in each row . There are 8 empty space . How many space are filled.

Mathematics
1 answer:
tatiyna2 years ago
7 0

Answer:

82 .

Step-by-step explanation:

9x 10 = 90 then 90-8 = 82 that how many spaces are filled .

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Since the altitude meets the triangle at a right angle it divides it into Similar triangles
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Help please with work
Dmitrij [34]

Answer:

200.96 ft²

Step-by-step explanation:

The question is on surface area of a closed cylinder

Formulae= SA=2 ×pi× r² + 2×pi×r×h

Where pi=3.14

SA= 2×3.14×2² + 2×3.14×2×14

SA=25.12+175.84

SA=200.96 ft²

4 0
3 years ago
(x-4)*(x-9)=0 what is x
Strike441 [17]

Answer:

x either equals to 4 of 9 so you can write it like x=4, 9

Step-by-step explanation:

Start by simplifying each sides of the equation.

x^2-13x+36=0

Then factor the left side of the equation.

(x-4)(x-9)=0

Set factors equal to 0

x-4=0 or x-9=0

x=4 or x=9

4 0
3 years ago
Read 2 more answers
I need help with number 9.<br> simple algebra.
Veseljchak [2.6K]

Answer:

C 1099

Step-by-step explanation:

The volume of a cylinder is given by

V = pi * r^2 *h

We know the radius is 5 and the height is 14

Substitute in what we know

V = 3.14 * 5^2 *14

V = 3.14 *25*14

V =1099  in^3

4 0
3 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
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