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son4ous [18]
3 years ago
12

Jim has 2 gems. He got 2 more on Monday and 5 more on Tuesday. How many does he have now?

Mathematics
2 answers:
Lunna [17]3 years ago
7 0

Answer:

9 gems

Step-by-step explanation:

2 + 2 + 5 = 9

mixer [17]3 years ago
3 0

Answer:9

Step-by-step explanation:2+2=4+5=9

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De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de
Sunny_sXe [5.5K]

Answer:

La masa del Sol es 2.509\times 10^{31} kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

M \propto \frac{r^{3}}{T^{2}}

M = k\cdot \frac{r^{3}}{T^{2}} (Eq. 1)

Donde:

r - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

T - Período oribital del satélite, medido en días.

k - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

M - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }

\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3} (Eq. 2)

Donde:

T_{M}, T_{E} - Períodos orbitales de la Luna y la Tierra, medidos en días.

r_{E}, r_{M} - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

M_{S}, M_{E} - Masas del Sol y la Tierra, medidos en kilogramos.

Si M_{E} = 75.97\times 10^{24}\,kg, T_{E} = 365.3\,d, T_{M} = 27.3\,d, r_{M} = 3.84\times 10^{5}\,km y r_{E} = 1.496\times 10^{8}\,km, entonces tenemos que la masa del Sol es:

M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}

M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)

M_{S} = 2.509\times 10^{31}\,kg

La masa del Sol es 2.509\times 10^{31} kilogramos.

7 0
3 years ago
Tell me how to shade the area on the grid that shows 7/8x3/4
viva [34]
If the grid is an 8x8: 

To solve this we need to convert 3/4 into a fraction x/8 so that they have the same denominator.

To do this we can set a porportion and find a common denominator. 4 x 2 = 8 so the common denominator would be 8 and the rule would be x 2 so 4 x 2 = 8 and 3 x 2 = 6

So we get 7/8 and 6/8

From top to bottom shade 7 spaces in a row

From left to right shade 6 spaces in a row

Fill in the spaces in between to make a square

I hope this helps!
8 0
3 years ago
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Match the description to the best example so that all terms have a matching example.
rusak2 [61]

Answer:

I'm pretty sure a set a decimal fractions is {1/4, 1/2, 3/4}

I think a set of whole numbers is {3, 4, 5.}

A set of integers might be {-2, -1, 0, +1.}

I'm am sure a set of natural numbers is {1, 2, 3.}

The set if rational numbers is {0.1, 0.2, 0.3} I think.

I am not that sure if my answers are right or not so sorry if this is incorrect.

5 0
3 years ago
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Approximate the square root of 500 to the nearest tenth. Show your work.
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\sqrt{500} \rightarrow \sqrt{5 * 10 * 10} \rightarrow 10\sqrt{5} This is an exact answer. the answer will be a bit larger than 20
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I am so stupid but I hope someone can help with this one.
Snezhnost [94]
I'm sure your not that stupid just post a qeustion and I will help you.
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3 years ago
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