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svlad2 [7]
3 years ago
7

How can polynomials be applied to financial situations?

Mathematics
2 answers:
Korvikt [17]3 years ago
7 0
In financial<span> planning, </span>polynomials<span> are used to calculate interest rate problems that determine how much money a person accumulates after a given number of years with a specified initial investment.</span>
cestrela7 [59]3 years ago
4 0
In financial planning, polynomials<span> are used to calculate interest rate problems that determine how much money a person accumulates after a given number of years with a specified initial investment.

Hope I Helped :))</span>
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A garden shop determines the demand function q = D(x) = 5x + 200 / 30x + 11 during early summer for tomato plants where q is the
cricket20 [7]

Answer: a) E(x)=\dfrac{-5945}{(30x+11)(5x+200)}, b) 0.7975, demand is inelastic, c) increase.

Step-by-step explanation:

Since we have given that

D(x)=\dfrac{5x+200}{30+11}

So, derivative w.r.t x would be

D'(x)=\dfrac{5(30x+11)-30(5x+200)}{(30x+11)^2}\\\\D'(x)=\dfrac{150x+55-150x-6000}{(30x+11)^2}\\\\D'(x)=\dfrac{5945}{(30x+11)^2}

As we know that

E(x)=\dfrac{-xD'(x)}{D(x)}\\\\\\E(x)=\dfrac{\dfrac{-(-)5945x}{(30x+11)^2}}{\dfrac{5x+200}{30x+11}}\\\\\\E(x)=\dfrac{5945x}{(30x+11)(5x+200)}

(b) Find the elasticity when x = 2.

So, we put x = 2, we get that

E(2)=\dfrac{5945\times 2}{(30(2)+11)((5(2)+200))}\\\\E(2)=\dfrac{11890}{(60+11)(10+200)}\\\\E(2)=\dfrac{11890}{71\times 210}\\\\E(2)=\dfrac{11890}{14910}\\\\E(2)=0.7975

Since, 0.7975 < 1, so the demand is inelastic.

(c) At $2 per plant, will a small increase in price cause the total revenue to increase or decrease?

The total revenue will also increase with increase in price.

As total revenue = price\times quantity

Hence, a) E(x)=\dfrac{-5945}{(30x+11)(5x+200)}, b) 0.7975, demand is inelastic, c) increase.

4 0
3 years ago
What is three times a number, minus 6, is equal to two times the number, plus 9
Usimov [2.4K]
3xN-6 = 2N+9
does this help or do you need the number
3 0
3 years ago
Read 2 more answers
In a lab experiment, 720 bacteria are placed in a Petri dish. The conditions are such that the number of bacteria is able to dou
MakcuM [25]

Answer:

22.4 hours

Step-by-step explanation:

The population of bacteria is modelled by the equation:

P=P_0e^{rt}

From the the question, the initial population of bacteria is 720.

So after 26 hours, we have:

P=2P_0

This implies that:

2P_0=P_0e^{26r}

2=e^{26r}

26r =  ln(2)

r =  \frac{ ln(2) }{26}

r = 0.0267

We want to find how long it will take for there to be 1310 bacteria present.

1310=720e^{0.0267t}

\frac{1310}{720}  =  {e}^{0.0267t}

\ln(\frac{1310}{720})  = {0.0267t}

0.59853= {0.0267t}  \\ t =  \frac{0.59853}{0.0267}

t = 22.417

To the nearest tenth , it will take 22.4 hours

6 0
3 years ago
Which ordered pair is the solution to the system of linear equations y =5x +8 and y= -4 x-1
aleksley [76]

Answer:

(-1,3)

y=5x+8 , y=-4x-1y=5x+8,y=−4x−1

Both sides have y on the left hand side so make the right hand side equal and solve for x

5x+8= -4x-15x+8=−4x−1

To solve for x , add 4x on both sides

9x+8=-19x+8=−1

Subtract 8 on both sides

9x=-99x=−9

Divide by 9 on both sides

x=-1x=−1

Now plug in -1 for x in the first equation and find out y

y=5x+8y=5x+8

y=5(-1)+8y=5(−1)+8

y=-5+8y=−5+8

y=3y=3

Ordered pair is (x,y) that is (-1,3)

Step-by-step explanation:

Mark me as brainliest plsss

8 0
2 years ago
Don't answer this please Brodies
Nitella [24]
Okeyuyyyyyyyyyyyyy but why did you post it then
8 0
2 years ago
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