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svlad2 [7]
3 years ago
7

How can polynomials be applied to financial situations?

Mathematics
2 answers:
Korvikt [17]3 years ago
7 0
In financial<span> planning, </span>polynomials<span> are used to calculate interest rate problems that determine how much money a person accumulates after a given number of years with a specified initial investment.</span>
cestrela7 [59]3 years ago
4 0
In financial planning, polynomials<span> are used to calculate interest rate problems that determine how much money a person accumulates after a given number of years with a specified initial investment.

Hope I Helped :))</span>
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Step-by-step explanation:

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If something is plentiful, possession of it will not increase your power. A resource need to be perceived as _____ to create dep
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2 years ago
What are the zeros of the quadratic function f(x) = 6x2 + 12x - 7?<br>​
mina [271]

Answer:

\frac{-6+\sqrt{78} }{6} and \frac{-6-\sqrt{78} }{6}

Step-by-step explanation:

We are asked that what are the zeros of the quadratic function f(x) = 6x² +12x -7.

So, we have to find the roots of the equation, f(x) = 6x² +12x -7 =0 ...... (1)

Since the quadratic function can not be factorized, so we have to apply Sridhar Acharya's formula.

This formula gives if, ax² +bx +c =0, the the two roots of the equation are

\frac{-b+\sqrt{b^{2}-4ac } }{2a} , \frac{-b-\sqrt{b^{2}-4ac } }{2a}

Therefore, in our case 'a' being 6, 'b' being 12 and 'c' being -7, the two roots of the equation (1) will be

\frac{-12+\sqrt{12^{2}-4*6*(-7) } }{2*6},  \frac{-12-\sqrt{12^{2}-4*6*(-7) } }{2*6}

= \frac{-12+\sqrt{312} }{12},\frac{-12-\sqrt{312} }{12}

=\frac{-6+\sqrt{78} }{6} and \frac{-6-\sqrt{78} }{6}

Hence, x= \frac{-6+\sqrt{78} }{6}

and x= \frac{-6-\sqrt{78} }{6}

(Answer)

9 0
4 years ago
Please help if good
Mariana [72]

Answer:

a=formula : Sum of all side

= 3+5+3

=11 ans

Step-by-step explanation:

formula is sum of all side

so add 3+5+3 ans =11

this is simple method

4 0
3 years ago
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