-14 = -5 + 3c
First, regroup your terms. / Your problem should look like:
Second, add 5 to both sides. / Your problem should look like:
Third, simplify -14 + 5 to -9. / Your problem should look like:
Fourth, divide both sides by 3. / Your problem should look like:
Fifth, simplify the fraction to 3. / Your problem should look like:
Sixth, switch your sides. / Your problem should look like:

Answer:
c = -3
Option 1 is the correct answer
Answer:
The area of the triangle with the given vertices is 10 square units
Step-by-step explanation:
x y
D 3 3
E 3 -1
F -2 -5
D 3 3
Area: A=Abs [(xd ye + xe yf + xf yd) - (yd xe + ye xf + yf xd)] /2
Absolute value: Abs
A = Abs { [(3)(-1)+(3)(-5)+(-2)(3)] - [(3)(3)+(-1)(-2)+(-5)(3)] } / 2
A = Abs [ (-3-15-6)-(9+2-15) ] / 2
A = Abs [ (-24)-(-4) ] / 2
A = Abs ( -24+4) / 2
A = Abs (-20) / 2
A = 20 / 2
A = 10 square units
Answer:
m∠QPR = 35° m∠QPM =40° m∠PRS = 30°
Step-by-step explanation:
ΔPRQ is a right triangle with right angle at R. So m∠QPR = 90 - 55 = 35
ΔQPM is a right triangle with right angle at M. So m∠QPM = 90 - 40 = 40
Arc RQ = 2(35) = 70 and arc SR = 2(25) = 50.
So arc PS = 180 - (arc RQ + arc SR) = 180 - (70 + 50) = 180 - 120 = 60
Now arc PS is the intercepted arc for ∠PRS.
Therefore, m∠PRS = 60/2 = 30
I used the fact that an inscribed angle has a measure 1/2 the measure of the intercepted arc several times. Also, I used the fact that the acute angles of a right triangle are complementary. And, finally I used the fact that an inscribed angle in a semicircle is a right angle.
I hope this helped.
The answer is 137,018,196
Explanation calculator