Question has missing details (Full question below)
Measurement error that is continuous and uniformly distributed from –3 to +3 millivolts is added to a circuit’s true voltage. Then the measurement is rounded to the nearest millivolt so that it becomes discrete. Suppose that the true voltage is 219 millivolts. What is the mean and variance of the measured voltage
Answer:
Mean = 219
Variance = 4
Step-by-step explanation:
Given
Let X be a random variable measurement error.
X has a discrete uniform distribution as follows
a = 219 - 3 = 216
b = 219 + 3 = 222
Mean or Expected value is calculated as follows;
E(x) = ½(216+222)
E(x) = ½ * 438
E(x) = 219
Variance is calculated as follows;
Var(x) = ((b-a+1)²-1)/12
Var(x) = ((222-216+1)²-1)/12
Var(x) = (7²-1)/12
Var(x) = 48/12
Var(x) = 4
She walked the most on Friday because you have to find the LCD. The LCD is 24.
For example, to change the denominator of 4 to 24, you must divide 24 divided by 4 which equals 6. Since your answer was 6, you have to multiply both numbers, which are 3 and 4, by 6.
So, 4 times 6 is 24. This is the denominator and 4 times 3 is 18. This is the numerator.
If you do the same with all of the fractions then you will have the fractions of, 18 over 24, 12 over 24, and 9 over 24.
Look at all the numerators (the number on top of the fraction) and decide which one is the biggest.
18 is the biggest and since the fraction 18 over 24 was originally 3 over 4, this means that she walked the most on Friday.
Hoped this helps!!
$1.36 will be added.
The discounted price is $17.00
Multiply that by .08
Answer:
9375
Step-by-step explanation:
