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Nastasia [14]
3 years ago
6

An adjustable ladder on the back of the firetruck is needed for firefighters to climb to very high buildings. The maximum angle

the ladder can raise is 70°. If the ladder has a maximum length of 100 feet, what is the distance, in feet, that the firetruck can park away from the building to reach its highest point?
Mathematics
1 answer:
torisob [31]3 years ago
3 0
Cos 70 = horizontal distance /
 100 horizontal distance = 100 cos 70  = 32.2feet
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trasher [3.6K]
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butalik [34]

Basically, you just move every individual point up, down, left, or right by the amount indicated.

For example, point G is graphed on the point (-3, -1). Moving it right 5 and up 1 will give you G’, which is (2,0)

T is graphed on the point (-1, -1). Moving it right 5 and up 1 will give you T’, which is (4,0)

B is graphed on the point (-3, -5). Moving it right 5 and up 1 will give you B’, which is

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7 0
3 years ago
The question is in the screenshot
Sidana [21]

Answer:

b. -36/77

Step-by-step explanation:

As 0 < x < \pi/2 => tan x > 0

As 0< y <  \pi/2 => tan y > 0

We have the formula:

  • \frac{1}{sin^{2}x } =1 + cot^{2}x => \frac{1}{(8/17)^{2} } = 1+cot^{2}x => cot^{2} x=225/64

As tan x = 1/(cotx) => tan^{2}x = \frac{1}{cot^{2}x} =\frac{1}{225/64} = \frac{64}{225}

As tan x > 0 => tan x = 8/15

  • \frac{1}{cos^{2}y } = 1+tan^{2}y => \frac{1}{(3/5)^{2} } = 1 + tan^{2} y => tan^{2}y=\frac{16}{9}

As tan y > 0 => tan y = 4/3

As tan (x-y)= \frac{tan x - tan y}{1+ tanx * tany} =\frac{(8/15)-(4/3)}{1+(8/15)*(4/3)} = \frac{-36}{77}  

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Which point is a solution to the system of equations graphed below?
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C.

This is because the x vale is clearly after the 6 and the y value is right on 5 
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