Given information:
Total animals = 13
Total legs = 40
Assumed all animals have their legs intact ...
Pig = 4 legs
Chicken = 2legs
Assumed all chickens:
Total legs = 2 x 13 = 26
Extra legs = 40 - 26 = 14
Extra legs belongs to the pig (each pig has extra 2 legs)
14 ÷ 2 = 7
There are 7 pigs
13 - 7 = 6
There are 6 chickens
---------- OR ALGEBRAICALLY --------
Let the number of pigs be x and number of chickens be y
pigs = x
chickens = y
x + y = 13 -------------- (1)
4x + 2y = 40 ---------- (2)
From (1):
x + y = 13
x = 13 - y -------------- sub into (2)
4(13 - y) + 2y = 40
52 - 4y + 2y = 40
52 - 2y = 40
2y = 52 - 40
2y = 12
y = 6 ----------- sub into (1)
x + 6 = 13
x = 13 - 6
x = 7
x = 7, y = 6
pigs = 7, chickens = 6
Answer:
So a 5% relative increase in R would mean a 20% relative increase in F
Step-by-step explanation:
First we need to remind the definition of relative increase of a variable.
For a variable A its relative increase is given by .
Using this, the relative increase in F is and similarly the relative increase in R is given by .
Let's then start by deriving F with respect to R:
thus
.
If we plug the value 5% in we get
Answer:
B
Step-by-step explanation:
Answer:
police officers
Step-by-step explanation:
That's a 20% increase.
So increase the police by 20% gets you:
Based on the wording of the question, if you want a greater percentage, the answer should be a single policeman more, thus 375,001.
5%x3000=150. The annual fee is $150. After 4 years, he would owe 600