Evaluate each expression individually and then combine like terms:
5 log₄(x²) = 5 = 5 = 5 = 5 log₂x = log₂x⁵
4 log₂(x) = log₂(x)⁴ = log₂(x⁴)
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log₂(2x + 1) - 5 log₄(x²) + 4 log₂(x)
= log₂(2x + 1) - log₂x⁵ + log₂(x⁴)
= log₂[(2x + 1)*(x⁴) ÷ x⁵]
= log₂
= log₂
Answer:
Step-by-step explanation:
Let's eliminate the c. Take the second and subtract the first. Take the third and subtract the first.
Now take 3 times the first and subtract from the second.
Substitute back to calculate b.
Substitute back to calculate c.
Sin (3 x) - cos (x)=
= sin (2x + x) - cos (x)=
= sin 2x * cos x + cos 2 x * sin x - cos x = ( using additional formulas )
= 2 sin x cos² x + ( cos² x - sin² x ) sin x - cos x =
= 2 sin x cos² x + ( 1 - sin² x - sin² x ) sin x - cos x =
= 2 sin x cos² x + ( 1 - 2 sin² x ) sin x - cos x =
= 2 sin x cos² x + sin x - 2 sin³ x - cos x
Answer: B )
Answer:
1)68
2)46
Step-by-step explanation:
Answer:
x in (-oo:+oo)
(21/2)*n = ((2*x)/8)*y // - ((2*x)/8)*y
(21/2)*n-(((2*x)/8)*y) = 0
(21/2)*n+(-1/4)*x*y = 0
21/2*n-1/4*x*y = 0 // - 21/2*n
-1/4*x*y = -(21/2*n) // : -1/4*y
x = (-(21/2*n))/(-1/4*y)
x = 42*n*y^-1
x = 42*n*y^-1
Step-by-step explanation:
Hope his helps :P