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Marat540 [252]
4 years ago
12

Restaurateur Denny Valentine is evaluating two sites, Raymondville and Rosenberg, for his next restaurant. He wants to prove tha

t Raymondville residents (population 1) dine out more often than Rosenberg residents (population 2). Denny plans to test this hypothesis using a random sample of 81 families from each suburb. His null hypothesis is __________.
Mathematics
1 answer:
Aleksandr-060686 [28]4 years ago
5 0

Answer:

\bar X_1 represent the sample for the sample 1

\bar X_2 represent the sample for the sample 2

s_1 represent the deviation for the sample 1

s_2 represent the deviation for the sample 2  

n_1 = 81 represent the sample size for the group 1

n_2 = 81 represent the sample size for the group 2

And on this case if we create the system of hypothesis we have this:

Null hypothesis :\mu_1 -\mu_2 \leq 0

Alternative hypothesis: \mu_1 -\mu_2 >0

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".  

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".  

On this caseHe wants to prove that Raymondville residents (population 1) dine out more often than Rosenberg residents (population 2). So this statement need to be on the alternative hypothesis. And the complement of the alternative hypothesis would be on the null hypothesis.  

Solution to the problem

We assume that we have the following statistics:

\bar X_1 represent the sample for the sample 1

\bar X_2 represent the sample for the sample 2

s_1 represent the deviation for the sample 1

s_2 represent the deviation for the sample 2  

n_1 = 81 represent the sample size for the group 1

n_2 = 81 represent the sample size for the group 2

And on this case if we create the system of hypothesis we have this:

Null hypothesis :\mu_1 -\mu_2 \leq 0

Alternative hypothesis: \mu_1 -\mu_2 >0

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Answer:

1 gamma = 15/8 alphas

Step-by-step explanation:

so we start by finding out what 1 gamma and 1 beta equals.

we know 4 gammas = 5 betas so if we divide by four on both sides we get:

1 gamma = 5/4 betas. we can apply that same procedure to 2 betas = 3 alphas and get 1 beta = 3/2 alphas

we know that 1 gamma = 5/4 betas and 1 beta = 3/2 alphas so how many alphas = 5/4 betas? using a proportion of ((3/2)/1) = ((x)/(5/4)) we can find that 5/4 betas = 15/8 alphas

therefore we know 1 gamma = 15/8 alphas or 1 and 7/8 alphas

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2 years ago
What is the value of f(3) in the function f(x)=5/6x+8
natita [175]

For this case we have a function of the form y = f (x), where f (x) = \frac {5} {6} x + 8

We must find the value of the function when x = 3, that is, we must find f (3). So:

f (3) = \frac {5} {6} (3) + 8\\f (3) = \frac {15} {6} +8\\f (3) = \frac {5} {2} +8\\f (3) = 2.5 + 8\\f (3) = 10.5

Sof (3) = 10.5

Answer:

f (3) = 10.5

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Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

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Help with geometry will mark brainliest for correct anwsers
Veseljchak [2.6K]
The first one is (-2,1)
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Please help I don’t understand
Archy [21]

Answer:

Step-by-step explanation:

when you draw a line through both it show that the are parallel and will never touch.

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